2012-12-28 17 views
2

我想使用问问模式使用akka Actor发出最简单的异步请求,但无论如何我都会收到akka.pattern.AskTimeoutException。我所拥有的是这样的:玩!异步行动akka AskTimeoutException

object Users extends Controller { 

    def newUser = { 
    val actor = Akka.system.actorOf(Props[UserRegistration]) 
    ActorAction[String](actor, "hello")(Ok(_)) 
    } 
} 

其中ActorAction是平时Async的包装:

object ActorAction { 

    def apply[A](actorRef: ActorRef, msg: AnyRef, timeout: Timeout = 5 seconds)(f: A => Result)(implicit m: Manifest[A]): Action[AnyContent] = { 
    Action { 
     AsyncResult { 
     ask(actorRef, msg, timeout).mapTo[A].asPromise.map(f) 
     } 
    } 
    } 

} 

和演员什么都不做,但会记录接收消息并返回它:

class UserRegistration extends Actor { 
    val log = Logging(context.system, this) 
    def receive = { 
    case u => log.info("received " + u); u 
    } 
} 

消息的记录工作正常。我尝试了一切,但没有任何工作。任何帮助都比欢迎!

播放:2.9.1 阿卡:2.0.2

堆栈跟踪:

[info] play - database [default] connected at jdbc:postgresql://localhost:5432/ss_dev 
[info] play - Application started (Dev) 
[info] play - Starting application default Akka system. 
[INFO] [12/28/2012 22:10:42.51] [application-akka.actor.default-dispatcher-1] [akka://application/user/$a] received hello 
[error] play - Waiting for a promise, but got an error: Timed out 
akka.pattern.AskTimeoutException: Timed out 
at akka.dispatch.DefaultPromise.result(Future.scala:875) [akka-actor.jar:2.0.2] 
at akka.dispatch.Await$.result(Future.scala:74) ~[akka-actor.jar:2.0.2] 
at play.api.libs.concurrent.AkkaPromise.await(Akka.scala:43) ~[play_2.9.1.jar:2.0.4] 
at play.api.libs.concurrent.Promise$class.await(Promise.scala:55) ~[play_2.9.1.jar:2.0.4] 
at play.api.libs.concurrent.AkkaPromise.await(Akka.scala:28) ~[play_2.9.1.jar:2.0.4] 
at play.api.libs.concurrent.Promise$class.value(Promise.scala:53) ~[play_2.9.1.jar:2.0.4] 
Caused by: akka.pattern.AskTimeoutException: Timed out 
at akka.pattern.PromiseActorRef$$anonfun$1.apply$mcV$sp(AskSupport.scala:274) ~[akka-actor.jar:2.0.2] 
at akka.actor.DefaultScheduler$$anon$6$$anon$7.run(Scheduler.scala:183) ~[akka-actor.jar:2.0.2] 
at akka.dispatch.TaskInvocation.run(AbstractDispatcher.scala:94) [akka-actor.jar:2.0.2] 
at akka.jsr166y.ForkJoinTask$AdaptedRunnableAction.exec(ForkJoinTask.java:1381) [akka-actor.jar:2.0.2] 
at akka.jsr166y.ForkJoinTask.doExec(ForkJoinTask.java:259) [akka-actor.jar:2.0.2] 
at akka.jsr166y.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:975) [akka-actor.jar:2.0.2] 

在此先感谢!

回答

2

你不回复消息sender ! u,请阅读阿卡参考文档:http://doc.akka.io

+0

感谢维克多!它确实有用!我认为接收方法的返回值是“回复”。非常感谢。 – Gerry

+0

嗨格里,接收方法不返回任何东西(单位),这是因为你可以有0..N“返回值” –