SUM DISTINCT MYSQL | WHERE CLAUSE

我想根据表（历史）SUM得到的结果，其中用户名包含'红色'并按月分组。在这里查询：SUM DISTINCT MYSQL | WHERE CLAUSE

select month(date), 
SUM(CASE WHEN status='success' THEN 1 ELSE 0 END) as total_sucess, 
SUM(CASE WHEN status='failed' THEN 1 ELSE 0 END) as total_failed 
from history 
where date between '201305%' AND '201311%' AND username like '%@red%' 
GROUP BY month(history.date);

结果：

+------------+--------------+--------------+ 
| month(date) | total_sucess | total_failed | 
+------------+--------------+--------------+ 
|   5 |  10960 |   3573 | 
|   6 |   2336 |   1202 | 
|   7 |   2211 |   1830 | 
|   8 |   5312 |   3125 | 
|   9 |   9844 |   5407 | 
|   10 |   6351 |   3972 | 
+------------+--------------+--------------+

的问题是，如何获取不同total_success和total_failed SUM？只是在一个查询？

我已经使用这个

select month(tgl), 
SUM(CASE WHEN status='success' THEN 1 ELSE 0 END) as total_sucess, 
SUM(DISTINCT (username) CASE WHEN status='success' THEN 1 ELSE 0 END) as distinct_total_sucess, 
SUM(CASE WHEN status='failed' THEN 1 ELSE 0 END) as total_failed, 
SUM(DISTINCT (username) CASE WHEN status='failed' THEN 1 ELSE 0 END) as distinct_failed_sucess 
from history_auth 
where tgl between '201305%' AND '201311%' AND username like '%@t.sel%' 
GROUP BY month(history_auth.tgl);

，但得到错误的SQL语法试过......我有这个:(不知道

来源

2013-10-18 user2893135

我不明白这个问题。你的意思是对于每个用户名，只计算1次成功和1次失败？ – Barmar

发布您的例外结果 –

如果这就是你想要的，你需要编写一个按用户名，状态和月份分组的子查询。 – Barmar

最好的我可以做出来的你的要求是，你想要的每个月是成功不同的用户名/失败的次数。

如果是这样，我认为你需要一双子选择来获取这些数字。

Rejigged查询（添加nother sub选择获得6个月，而不是依赖所有月份的代表。

SELECT Sub1.aMonth, 
SUM(CASE WHEN history.status='success' THEN 1 ELSE 0 END) as total_sucess, 
SUM(CASE WHEN history.status='failed' THEN 1 ELSE 0 END) as total_failed, 
IFNULL(SuccessCount, 0), 
IFNULL(FailedCount, 0) 
FROM 
(
    SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 0 MONTH)) AS aMonth 
    UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 1 MONTH)) 
    UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 2 MONTH)) 
    UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 3 MONTH)) 
    UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 4 MONTH)) 
    UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 5 MONTH)) 
    UNION SELECT MONTH(DATE_SUB('2013-11-01', INTERVAL 6 MONTH)) 
) Sub1 
LEFT OUTER JOIN history 
ON MONTH(history.date) = Sub1.aMonth 
AND username LIKE '%@red%' 
LEFT OUTER JOIN 
(
    SELECT MONTH(date) AS aMonth, COUNT(DISTINCT username) AS SuccessCount 
    FROM history 
    WHERE status='success' 
    AND username LIKE '%@red%' 
    GROUP BY MONTH(date) 
) Sub2 
ON Sub1.aMonth = Sub2.aMonth 
LEFT OUTER JOIN 
(
    SELECT MONTH(date) AS aMonth, COUNT(DISTINCT username) AS FailedCount 
    FROM history 
    WHERE status='failed' 
    AND username LIKE '%@red%' 
    GROUP BY MONTH(date) 
) Sub3 
ON Sub1.aMonth = Sub3.aMonth 
GROUP BY Sub1.aMonth, SuccessCount, FailedCount

来源

2013-10-18 10:44:43 Kickstart

SUM DISTINCT MYSQL | WHERE CLAUSE

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