2009-11-23 34 views

回答

14

我一直在使用下面的Mock和Moq来允许在我的单元测试中设置各种条件。首先,HttpContextBase模拟:

public static Mock<HttpContextBase> GetHttpContextMock(bool isLoggedIn) 
    { 
     var context = new Mock<HttpContextBase>(); 
     var request = new Mock<HttpRequestBase>(); 
     var response = new Mock<HttpResponseBase>(); 
     var session = new Mock<HttpSessionStateBase>(); 
     var server = new Mock<HttpServerUtilityBase>(); 
     var principal = AuthenticationAndAuthorization.GetPrincipleMock(isLoggedIn); 

     context.SetupGet(c => c.Request).Returns(request.Object); 
     context.SetupGet(c => c.Response).Returns(response.Object); 
     context.SetupGet(c => c.Session).Returns(session.Object); 
     context.SetupGet(c => c.Server).Returns(server.Object); 
     context.SetupGet(c => c.User).Returns(principal.Object); 

     return context; 
    } 

每个属性可能提供一个有用的模拟在这里成立。这样一来,如果我需要添加类似引荐,我可以只使用:

Mock.Get(controller.Request).Setup(s => s.UrlReferrer).Returns(new Uri("http://blah.com/"); 

的“GetPrincipleMock”的方法就是建立用户。它看起来像这样:

public static Mock<IPrincipal> GetPrincipleMock(bool isLoggedIn) 
    { 
     var mock = new Mock<IPrincipal>(); 

     mock.SetupGet(i => i.Identity).Returns(GetIdentityMock(isLoggedIn).Object); 
     mock.Setup(i => i.IsInRole(It.IsAny<string>())).Returns(false); 

     return mock; 
    } 

    public static Mock<IIdentity> GetIdentityMock(bool isLoggedIn) 
    { 
     var mock = new Mock<IIdentity>(); 

     mock.SetupGet(i => i.AuthenticationType).Returns(isLoggedIn ? "Mock Identity" : null); 
     mock.SetupGet(i => i.IsAuthenticated).Returns(isLoggedIn); 
     mock.SetupGet(i => i.Name).Returns(isLoggedIn ? "testuser" : null); 

     return mock; 
    } 

现在,在测试我的控制器的设置是这样的:

var controller = new ProductController(); 
var httpContext = GetHttpContextMock(true); //logged in, set to false to not be logged in 

ControllerContext controllerContext = new ControllerContext(httpContext.Object, new RouteData(), controller); 
controller.ControllerContext = controllerContext; 

这是冗长设置的一点点,但一旦你有一切就绪,测试各种的条件变得更容易。

+0

完美。答案仍然相关。+ 1 – joshmcode 2016-11-02 21:22:25

7

这不是最简单的事情,但它可以做到。 User属性只是委托给Controller.HttpContext.User。两者都是非虚拟的只读属性,所以你不能对它们做任何事情。但是,Controller.HttpContext委托给ControllerBase.ControllerContext,它是一个可写属性。

因此,在执行被测系统(SUT)之前,您可以将Test Double HttpContextBase分配给Controller.ControllerContext。使用Moq,它看起来像这样:

var user = new GenericPrincipal(new GenericIdentity(string.Empty), null); 
var httpCtxStub = new Mock<HttpContextBase>(); 
httpCtxStub.SetupGet(ctx => ctx.User).Returns(user); 

var controllerCtx = new ControllerContext(); 
controllerCtx.HttpContext = httpCtxStub.Object; 

sut.ControllerContext = controllerCtx; 

然后调用您的操作并验证返回结果是否为RedirectResult。

此测试利用了隐式知识,当您使用空名称创建GenericIdentity时,它将为IsAuthenticated返回false。您可以考虑通过使用Mock<IIdentity>来更明确地进行测试。

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