坚持更新列值

这是我的表likes坚持更新列值

id type parent country votes 
1 1 0  US  0 # This value need to be 9 
2 2 1  US  6 
19 3 1  US  3 
3 3 2  US  3 
7 3 2  US  3 
4 10 3  US  1 
5 10 3  US  1 
6 10 3  US  1 
10 10 7  US  1 
9 10 7  US  1 
8 10 7  US  1 
20 10 19  US  1 
21 10 19  US  1 
22 10 19  US  1

我做了一个脚本，在表中更新的总票数。

这里，type 10 updates type 3，type 3 updates 2 and 1，type 2 updates 1

你会看到它是如何工作当u运行我的脚本。

这里，id 1需要为9，并且每次脚本运行时都不应刷新。其他人不。但我无法找到一种方法来更新1而不会使其价值翻倍。

你能帮我找个办法吗？

继承人的脚本。

$conn = connect(); 

$what = 10; 
$pathType = 15; 

while ($pathType >=2) 
{ 
$stmt = $conn->prepare("select max(type) as type from likes where type < :type and country = 'US'"); 
$stmt->bindParam(':type', $pathType); 
$stmt->execute(); 
$pathData = $stmt->fetch(); 
$pathType = $pathData['type']; 
echo 'Path Type is '.$pathType.'<br>'; 

    $stmt = $conn->prepare("select sum(votes) as votes, parent as parent from likes where type=:type group by parent"); 
    $stmt->bindParam(':type', $pathData['type']); 
    $stmt->execute(); 
    $rows = $stmt->rowCount(); 

     while($row = $stmt->fetch()) { 
      echo $row['parent']." ".$row['votes']; 
      echo "<br>"; 

      if($row['parent'] == 1){ 
      echo 'Passed Level 1<br>'; 
       $wtf = $conn->prepare("update likes set votes=votes+:votes where id=:parent"); 
      }else{ 
       $wtf = $conn->prepare("update likes set votes=:votes where id=:parent"); 
      } 

      $wtf->bindParam(':votes', $row['votes']); 
      $wtf->bindParam(':parent', $row['parent']); 
      $wtf->execute(); 
     } 
    echo "-----------------------------------------------<br>"; 
}

这里，r的产生的情况下，你需要他们：

-- -------------------------------------------------------- 
-- Host:       127.0.0.1 
-- Server version:    5.5.25 - MySQL Community Server (GPL) 
-- Server OS:     Win64 
-- HeidiSQL version:    7.0.0.4053 
-- Date/time:     2013-05-17 14:41:11 
-- -------------------------------------------------------- 

/*!40101 SET @[email protected]@CHARACTER_SET_CLIENT */; 
/*!40101 SET NAMES utf8 */; 
/*!40014 SET FOREIGN_KEY_CHECKS=0 */; 

-- Dumping database structure for wwp-db 
DROP DATABASE IF EXISTS `wwp-db`; 
CREATE DATABASE IF NOT EXISTS `wwp-db` /*!40100 DEFAULT CHARACTER SET utf8 */; 
USE `wwp-db`; 


-- Dumping structure for table wwp-db.likes 
DROP TABLE IF EXISTS `likes`; 
CREATE TABLE IF NOT EXISTS `likes` (
    `id` int(10) NOT NULL AUTO_INCREMENT, 
    `type` tinyint(1) DEFAULT '0', 
    `parent` int(10) DEFAULT '0', 
    `country` varchar(2) DEFAULT NULL, 
    `votes` int(10) DEFAULT '0', 
    PRIMARY KEY (`id`) 
) ENGINE=MyISAM AUTO_INCREMENT=4176 DEFAULT CHARSET=utf8 ROW_FORMAT=DYNAMIC; 

-- Dumping data for table wwp-db.likes: 14 rows 
/*!40000 ALTER TABLE `likes` DISABLE KEYS */; 
INSERT IGNORE INTO `likes` (`id`, `type`, `parent`, `country`, `votes`) VALUES 
    (1, 1, 0, 'US', 9), 
    (2, 2, 1, 'US', 6), 
    (3, 3, 2, 'US', 3), 
    (4, 10, 3, 'US', 1), 
    (5, 10, 3, 'US', 1), 
    (6, 10, 3, 'US', 1), 
    (7, 3, 2, 'US', 3), 
    (8, 10, 7, 'US', 1), 
    (9, 10, 7, 'US', 1), 
    (10, 10, 7, 'US', 1), 
    (19, 3, 1, 'US', 3), 
    (20, 10, 19, 'US', 1), 
    (21, 10, 19, 'US', 1), 
    (22, 10, 19, 'US', 1); 
/*!40000 ALTER TABLE `likes` ENABLE KEYS */; 
/*!40014 SET FOREIGN_KEY_CHECKS=1 */; 
/*!40101 SET [email protected]_CHARACTER_SET_CLIENT */;

来源

2013-05-17 Norman

第一行中喜欢不符合您的if语句的条件中的第一个实例。

if($row['parent'] == 1){ 
    echo 'Passed Level 1<br>'; //This doesn't apply to row with id 1 - but does to one with parent id 1 
    $wtf = $conn->prepare("update likes set votes=votes+:votes where id=:parent"); 
}else{ 
//Does not affect row with id 1 as it has a parent of 0 
$wtf = $conn->prepare("update likes set votes=:votes where id=:parent"); 
}

编辑：好了，所以它的执行这样的：和更新行0

$wtf = $conn->prepare("update likes set votes=votes+:votes where id=:parent");

当它达到与父ID 1行，

您指示它添加到票不会设置为一个值，每次刷新时自然会添加更多，如果您希望它停止在某个值上，则向查询或代码添加另一个条件

来源

2013-05-17 09:24:20 allen213

它会更新值9. P这里的问题是，如果你刷新页面，它将会是15甚至更多。 – Norman

任何想法如何做到这一点？我已经用完了想法。 – Norman

如果我改变它，它会给我6而不是9。 – Norman

坚持更新列值

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