好,不与公用表表达式递归,你需要硬连线几件事情。 如果您有超过4个COL1的值,它会变得更乏味;如果它涉及一个非常重要的业务问题,请考虑为此编写一个UDx。
但是 - 否则 - 这里是一个工程 - 包括在WITH子句的第一个公用表表达式输入:
WITH
input(col1,col1_time,col2,col2_time) AS (
SELECT 'A',TIME '09:20:00','E',TIME '09:35:00'
UNION ALL SELECT 'A',TIME '09:20:00','F',TIME '09:36:00'
UNION ALL SELECT 'A',TIME '09:20:00','G',TIME '09:40:00'
UNION ALL SELECT 'A',TIME '09:20:00','H',TIME '09:59:00'
UNION ALL SELECT 'B',TIME '09:25:00','E',TIME '09:35:00'
UNION ALL SELECT 'B',TIME '09:25:00','F',TIME '09:36:00'
UNION ALL SELECT 'B',TIME '09:25:00','G',TIME '09:40:00'
UNION ALL SELECT 'B',TIME '09:25:00','H',TIME '09:59:00'
UNION ALL SELECT 'C',TIME '09:30:00','E',TIME '09:35:00'
UNION ALL SELECT 'C',TIME '09:30:00','F',TIME '09:36:00'
UNION ALL SELECT 'C',TIME '09:30:00','G',TIME '09:40:00'
UNION ALL SELECT 'C',TIME '09:30:00','H',TIME '09:59:00'
UNION ALL SELECT 'D',TIME '09:50:00','H',TIME '09:59:00'
)
,
col1_A AS (
SELECT
col1
, col2
FROM input
WHERE col1='A'
ORDER BY ABS(TIMESTAMPDIFF('SECOND',col1_time::TIMESTAMP,col2_time::TIMESTAMP))
LIMIT 1
)
,
col1_B AS (
SELECT
col1
, col2
FROM input
WHERE col1='B'
AND col2 NOT IN (
SELECT col2 FROM col1_A
)
ORDER BY ABS(TIMESTAMPDIFF('SECOND',col1_time::TIMESTAMP,col2_time::TIMESTAMP))
LIMIT 1
)
,
col1_C AS (
SELECT
col1
, col2
FROM input
WHERE col1='C'
AND col2 NOT IN (
SELECT col2 FROM col1_A
UNION ALL SELECT col2 FROM col1_B
)
ORDER BY ABS(TIMESTAMPDIFF('SECOND',col1_time::TIMESTAMP,col2_time::TIMESTAMP))
LIMIT 1
)
,
col1_D AS (
SELECT
col1
, col2
FROM input
WHERE col1='D'
AND col2 NOT IN (
SELECT col2 FROM col1_A
UNION ALL SELECT col2 FROM col1_B
UNION ALL SELECT col2 FROM col1_C
)
ORDER BY ABS(TIMESTAMPDIFF('SECOND',col1_time::TIMESTAMP,col2_time::TIMESTAMP))
LIMIT 1
)
SELECT * FROM col1_A
UNION ALL SELECT * FROM col1_B
UNION ALL SELECT * FROM col1_C
UNION ALL SELECT * FROM col1_D
;
如果不是你希望什么,我不会感到惊讶...
玩的开心...
马尔科理智
我敢肯定,这需要递归CTE的,而且我不认为Vertica的支持的。 –
@GordonLinoff:可以请您为sql server编写查询 –