字符串新行字符

Question

我有这样的字符串：

"“It's hard to beat a person who never gives up.”\n ―\n Babe Ruth" 

其中我已成功地剥离该：

“It's hard to beat a person who never gives up.”\n ―\n Babe Ruth 

使用该正则表达式：

/^"(.*)"/ 

现在我需要去掉这两个新的行字符，并删除多余的空白。这是我想回报：

=> "It's hard to beat a person who never gives up." - Babe Ruth 

任何人都可以给我一个提示吗？

Answer 1

我不是你问100％清楚，但我想你想是这样的：

s = "“It's hard to beat a person who never gives up.”\n ―\n Babe Ruth" 
s.gsub(/\s+/, " ") 
# => "“It's hard to beat a person who never gives up.” ― Babe Ruth" 

，上面写着：“用空格替换任何一个或多个空格字符“。

Answer 2

使用String#squeeze删除连续的字符和String#gsub删除换行符：

string = "\“It's hard to beat a person who never gives up.\”\n ―\n Babe Ruth'" 

string.squeeze(' ').gsub("\n", '')                        
#=> "“It's hard to beat a person who never gives up.” ― Babe Ruth'" 

http://ruby-doc.org/core-2.0.0/String.htm

Answer 3

有不同的方式去了解这一点，这取决于你想要的最终结果是什么。

作为一个起点：

# encoding: UTF-8 

puts "“It's hard to beat a person who never gives up.”\n ―\n Babe Ruth".gsub(/\s\s+/, ' ') 
# >> “It's hard to beat a person who never gives up.” ― Babe Ruth 

你的样品结果不具有弯引号或连字符（你有一个破折号）：

puts "“It's hard to beat a person who never gives up.”\n ―\n Babe Ruth".gsub(/\s\s+/, ' ').tr('“”―', '""-') 
# >> "It's hard to beat a person who never gives up." - Babe Ruth