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这是我的某个程序的代码。但是,什么是杀害我的是,在功能getTotalX
,在内部如果块的for循环,当标志break语句后更新为0,事实上,它得到更新回到1。这是为什么发生?我认为break语句可以帮助我摆脱for循环,并直接转到下一个语句。break语句后分配的值会发生什么?
#include <stdio.h>
int getTotalX(int a_size, int* a, int b_size, int* b){
int min = a[a_size-1];
int max = b[0];
int count = 0;
for(int i = min; i <= max; i++){
int flag1 = 1, flag2 = 1;
for(int j = 0; j < a_size; j++){
printf("In array a,value of %d mod %d is %d \n",i,a[j],i%a[j]);
if((i % a[j]) != 0){
int flag1 = 0;
printf("flag1 set to 0. Check flag1 = %d\n",flag1);
break;
}
}
printf("Checkpoint2, value of flag1 = %d\n",flag1);
if(flag1 != 0){
for(int k =0; k < b_size; k++){
printf("In array b,value of %d mod %d is %d \n",b[k],i,b[k]%i);
if((b[k] % i) != 0){
int flag2 = 0;
printf("flag2 set to 0. Check flag2 = %d\n",flag2);
break;
}
}
}
printf("Checkpoint3, value of flag2 = %d\n",flag2);
if((flag1 == 1) && (flag2 == 1)){
printf("Value of flag1 = %d and flag2 = %d\n",flag1,flag2);
printf("%d \n ",i);
count++;
}
}
return(count);
}
int main() {
int n;
int m;
scanf("%d %d", &n, &m);
int *a = malloc(sizeof(int) * n);
for(int a_i = 0; a_i < n; a_i++){
scanf("%d",&a[a_i]);
}
int *b = malloc(sizeof(int) * m);
for(int b_i = 0; b_i < m; b_i++){
scanf("%d",&b[b_i]);
}
int total = getTotalX(n, a, m, b);
printf("%d\n", total);
return 0;
}
所有的打印声明都是为了帮助我弄清楚我哪里出错了。我可以改变逻辑来使其工作,但请帮助我理解为什么会发生这种情况?
的好处['-Wshadow'](https://stackoverflow.com/questions/25151524/get-warning-when-a-variable-is-shadowed)不能被低估。 – dhke
哦,太棒了!哇。 – momo