使用if/elif语句遇到问题

Question

对于代码中的“狗”部分，它完美地工作并完成它应有的功能。但是，如果在开始时为输入问题输入“Cat”，它仍会继续并执行代码的狗部分。

即使我在代码中写道，如果问题==“猫”或“猫”的答案，那么它应该做这个部分而不是狗部分。

import time 
import sys 

animal=input("What animal do you want to calculate the age of? - Possible choices: Cat/Dog") 

if animal=="Dog"or"dog": 
    age=int(input("How old is your Dog?")) 
    if age==1: 
     print("Calculating the age of the Dog...") 
     time.sleep(1) 
     print("The age of the animal is: 11") 
    elif age==2: 
     print("Calculating the age of the Dog...") 
     time.sleep(1) 
     print("The age of the animal is: 11") 
    else: 
     age=age-2 
     print("Calculating the age of the Dog...") 
     time.sleep(1) 
     agecalculation=age*4+22 
     print("The age of the animal is:",agecalculation) 
     time.sleep(2) 
     print("End of program.") 
     time.sleep(2) 
     sys.exit() 

elif animal=="Cat"or"cat": 
    age=int(input("How old is your Cat?")) 
    if age==1: 
     print("Calculating the age of the Cat...") 
     time.sleep(1) 
     print("The age of the animal is: 15") 
    elif age==2: 
     print("Calculating the age of the Cat...") 
     time.sleep(1) 
     print("The age of the animal is: 25") 
    else: 
     age=age-2 
     print("Calculating the age of the Cat...") 
     time.sleep(1) 
     agecalculation=age*4+25 
     print("The age of the animal is:",agecalculation) 
     time.sleep(2) 
     print("End of program.") 
     time.sleep(2) 
     sys.exit() 
else: 
    print("That is not an animal, or isn't on the list specified") 
    animal=input("What animal do you want to calculate the age of? - Possible choices: Cat/Dog")    

Answer 1

以下if测试将始终评估为true：

if animal=="Dog" or "dog": 

向上述作品，好像有括号：

if (animal=="Dog") or ("dog"): 

的or的第二部分将，下Python的规则，总是为true：非空字符串有真正的布尔值。

这里是工作的三个选项：

if animal=="Dog" or animal == "dog": 

if animal in ("Dog", "dog"): 

if animal.lower() =="dog": 

更多：这些问题可以在Python的方便交互命令提示符容易测试。例如，观察"Dog"和""布尔值：

>>> bool("Dog"), bool("") 
(True, False) 

而且，这里是合并报表：

>>> bool('Cat' == 'Dog' or 'dog') 
True 

Answer 2

在Python中，根本没有空字符串被评价为true，如：

if "something": 
    print("True") 
else 
    print("False") 

将始终打印True

所以你需要设置你是否喜欢：

if animal=="Dog" or animal=="dog": 
    #Do something with dog 
elif animal=="Cat" or animal=="cat": 
    #Do something with cat 
else: 
    #Do something else 

Answer 3

你会想编辑您的代码，例如：

import time 
import sys 

animal=input("What animal do you want to calculate the age of? - Possible choices: Cat/Dog") 

if animal=="Dog"or animal=="dog": 
    age=int(input("How old is your Dog?")) 
    if age==1: 
     print("Calculating the age of the Dog...") 
     time.sleep(1) 
     print("The age of the animal is: 11") 
    elif age==2: 
     print("Calculating the age of the Dog...") 
     time.sleep(1) 
     print("The age of the animal is: 11") 
    else: 
     age=age-2 
     print("Calculating the age of the Dog...") 
     time.sleep(1) 
     agecalculation=age*4+22 
     print("The age of the animal is:",agecalculation) 
     time.sleep(2) 
     print("End of program.") 
     time.sleep(2) 
     sys.exit() 

elif animal=="Cat"or animal == "cat": 
    age=int(input("How old is your Cat?")) 
    if age==1: 
     print("Calculating the age of the Cat...") 
     time.sleep(1) 
     print("The age of the animal is: 15") 
    elif age==2: 
     print("Calculating the age of the Cat...") 
     time.sleep(1) 
     print("The age of the animal is: 25") 
    else: 
     age=age-2 
     print("Calculating the age of the Cat...") 
     time.sleep(1) 
     agecalculation=age*4+25 
     print("The age of the animal is:",agecalculation) 
     time.sleep(2) 
     print("End of program.") 
     time.sleep(2) 
     sys.exit() 
else: 
    print("That is not an animal, or isn't on the list specified") 
    animal=input("What animal do you want to calculate the age of? - Possible choices: Cat/Dog")    

当你做if animal == "Dog" or "dog"，它正在评估是否animal == "Dog"，以及如果"dog"。您可以使用animal.lower() == "dog"，或使用上面编辑的代码。

Answer 4

明显的错误已经指出的pasztorpisti：

animal=='Cat'or'cat'是不是你想要的。请使用animal.lower()=='cat'或animal in ['cat', 'Cat']或其他方法。

我也认为你的整个代码可能会减少很多。也许你可以抓住从下面的代码片段的一个或两个想法：

def dogAge(age): 
    return 11 if age < 3 else age * 4 + 14 

def catAge(age): 
    if age == 1: return 15 
    if age == 2: return 25 
    return age * 4 + 17 

animal = input("What animal do you want to calculate the age of? - Possible choices: Cat/Dog").lower() 
if animal not in ['cat', 'dog']: 
    print("That is not an animal, or isn't on the list specified") 
    sys.exit(0) 

age = int(input("How old is your {}?".format(animal))) 

animalAge = {'cat': catAge, 'dog': dogAge}[animal](age) 

print("The age of the animal is {}.".format(animalAge)) 

Answer 5

我怀疑（不包括在检查的话），这个问题是不是你的逻辑，你的条件。

animal == "Dog" or "dog"的计算结果为(animal == "Dog") or "dog"由于“dog”是一个非空字符串，它将始终计算为True。试试animal == "Dog" or animal == "dog"，还是更好些animal in ("Dog", "dog")或animal.lower() == "dog"？