转换为字符串，删除特殊字符和更换

Question

我需要我的字符串转换，使其制作成特殊格式

例如：

string = "the cow's milk is a-okay!" 

converted string = "the-cows-milk-is-a-okay" 

Answer 1

import re 

s = "the cow's milk is a-okay!" 
s = re.sub(r'[^a-zA-Z\s-]+', '', s) # remove anything that isn't a letter, space, or hyphen 
s = re.sub(r'\s+', '-', s) # replace all spaces with hyphens 
print(s) # the-cows-milk-is-a-okay 

这里一个“空间”是任何包含制表符和换行符的空白字符。要更改此设置，请将\s替换为实际空格字符。

多个空格的运行将被替换为一个连字符。要更改此设置，请在第二次拨打re.sub时删除+。

Answer 2

这个怎么样（缺点是无法维持的连字符-），

import string 

s = "the cow's milk is a-okay!" 

table = string.maketrans(" ", "-") 
new_s = s.translate(table, string.punctuation) 

print(new_s) 
# the-cows-milk-is-aokay 

Answer 3

>>> string = "the cow's milk is a-okay!" 
>>> string 
"the cow's milk is a-okay!" 
>>> string = string.replace(' ','-') 
>>> for char in string: 
...  if char in "?.!:;/'": 
...    string = string.replace(char,'') 
... 
>>> string 
'the-cows-milk-is-a-okay' 

Answer 4

一个简单的生成器表达式可以用来实现这一点：

>>> s = "the cow's milk is a-okay!" 
>>> ''.join(('-' if el == " " else el if el not in "?.!:;/'" else "" for el in s)) 
'the-cows-milk-is-a-okay' 
>>>