从字符串NSDate

Question

我有一个字符串“2012-09-16 23:59:59 JST” 我想将此日期字符串转换为NSDate。

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
[dateFormatter setDateFormat:@"yyyy-MM-dd hh:mm:ss Z"]; 
NSDate *capturedStartDate = [dateFormatter dateFromString: @"2012-09-16 23:59:59 JST"]; 
NSLog(@"%@", capturedStartDate); 

但它不工作。它给予null值。请帮助..

Answer 1

当使用24小时时间，小时符必须是这样一个大写的H：

[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss Z"]; 

检查这里的正确说明符：http://unicode.org/reports/tr35/tr35-6.html#Date_Format_Patterns

但是，你需要设置区域设置的日期格式：

// Set the locale as needed in the formatter (this example uses Japanese) 
[dateFormat setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"ja_JP"]]; 

全部工作代码：

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss zzz"]; 
[dateFormatter setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"ja_JP"]]; 
NSDate *capturedStartDate = [dateFormatter dateFromString: @"2012-09-16 23:59:59 JST"]; 
NSLog(@"Captured Date %@", [capturedStartDate description]); 

输出（GMT）：

Captured Date 2012-09-16 14:59:59 +0000 

Answer 2

NSString *dateString = @"01-02-2010"; 
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 

// this is imporant - we set our input date format to match our input string 
// if format doesn't match you'll get nil from your string, so be careful 

[dateFormatter setDateFormat:@"dd-MM-yyyy"]; 
NSDate *dateFromString = [[NSDate alloc] init]; 
// end 
dateFromString = [dateFormatter dateFromString:dateString]; 
[dateFormatter release]; 

Answer 3

NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss Z"]; 
NSDate *capturedStartDate = [dateFormatter dateFromString: @"2012-09-16 23:59:59 GMT-08:00"]; 
NSLog(@"%@", capturedStartDate);