SQL - 获取给定组的最小最大日期，并且有中断日期

Question

我正在尝试查找处理日期中给定值的下列数据的最小值和最大值处理日期（请注意，行不会在周末处理，我不想将它们分解成两组不同的，如果他们有相同的值）

SELECT 1, 'A',to_date('10/01/2012','dd/mm/yyyy'), 10, to_date('11/01/2012','dd/mm/yyyy') FROm DUAL 
UNION ALL SELECT 1, 'A',to_date('11/01/2012','dd/mm/yyyy'), 10, to_date('12/01/2012','dd/mm/yyyy') FROm DUAL 
UNION ALL SELECT 1, 'A',to_date('12/01/2012','dd/mm/yyyy'), 9, to_date('13/01/2012','dd/mm/yyyy') FROm DUAL 
UNION ALL SELECT 1, 'A',to_date('13/01/2012','dd/mm/yyyy'), 9, to_date('14/01/2012','dd/mm/yyyy') FROm DUAL 
UNION ALL SELECT 1, 'A',to_date('16/01/2012','dd/mm/yyyy'), 9, to_date('17/01/2012','dd/mm/yyyy') FROm DUAL 
UNION ALL SELECT 1, 'A',to_date('17/01/2012','dd/mm/yyyy'), 10, to_date('18/01/2012','dd/mm/yyyy') FROm DUAL 
UNION ALL SELECT 1, 'A',to_date('18/01/2012','dd/mm/yyyy'), 10, to_date('19/01/2012','dd/mm/yyyy') FROm DUAL; 

我尝试（我知道是错的）

SELECT id, cd, value, min(p_dt) min_dt, max(p_dt) max_dt FROM T 
group by id, cd, value; 

这将返回

ID CD VALUE MIN_DT      MAX_DT 
---------------------------------------------------------------------------------- 
1 A 9 January, 12 2012 00:00:00+0000 January, 16 2012 00:00:00+0000 
1 A 10 January, 10 2012 00:00:00+0000 January, 18 2012 00:00:00+0000 

我想回到什么是

ID CD VALUE MIN_DT      MAX_DT 
---------------------------------------------------------------------------------- 
1 A 9 January, 12 2012 00:00:00+0000 January, 16 2012 00:00:00+0000 
1 A 10 January, 10 2012 00:00:00+0000 January, 11 2012 00:00:00+0000 
1 A 10 January, 17 2012 00:00:00+0000 January, 18 2012 00:00:00+0000 

我尝试不同的方法进行查询，但我不能拿出一个工作查询。

SQL FIDDLE

Answer 1

不知道你想要什么？你没有正确的数据按日期进行分区。你的日期是独一无二的，除非你的意思是你的i_dt必须等于p_dt。即使按日期而不是数值进行分区，您也将获得所有行，如同在简单选择中一样。 在我的例子中，我按值分区。在唯一值中可能只有一个最大日期和一个最短日期。检查输出：

SELECT id, cd, i_dt, p_dt, value 
, To_Char(MIN(p_dt) OVER (PARTITION BY value), 'Mon, DD YYYY HH24:MI:SS') min_dt 
, To_Char(MAX(p_dt) OVER (PARTITION BY value), 'Mon, DD YYYY HH24:MI:SS') max_dt 
FROM t 
/

ID CD I_DT   P_DT VALUE MIN_DT     MAX_DT 
--------------------------------------------------------------------------------------- 
1  A 1/14/2012 1/13/2012 9 Jan, 12 2012 00:00:00 Jan, 16 2012 00:00:00 
1  A 1/17/2012 1/16/2012 9 Jan, 12 2012 00:00:00 Jan, 16 2012 00:00:00 
1  A 1/13/2012 1/12/2012 9 Jan, 12 2012 00:00:00 Jan, 16 2012 00:00:00 
1  A 1/19/2012 1/18/2012 10 Jan, 10 2012 00:00:00 Jan, 18 2012 00:00:00 
1  A 1/18/2012 1/17/2012 10 Jan, 10 2012 00:00:00 Jan, 18 2012 00:00:00 
1  A 1/12/2012 1/11/2012 10 Jan, 10 2012 00:00:00 Jan, 18 2012 00:00:00 
1  A 1/11/2012 1/10/2012 10 Jan, 10 2012 00:00:00 Jan, 18 2012 00:00:00 

Answer 2

这是网站上寻求解决同样问题的其他一些问题。例子是here和here，这些只是我提供答案的问题。

这个问题有点复杂，因为忽略周末的要求。这个问题似乎相对比较简单，我将很快解释。

您的问题不包括表格中所有列的列名称。我假设第一个日期是过程日期，另一个日期对于此查询并不重要。这可能是错误的假设。

从这个问题来看，如果在一个工作日（周一到周四）的第二天有一个匹配的行，它看起来像一个组。对于星期五，下周一需要有匹配的行。我处理这个问题的方法是，如果是星期五，或者在其他情况下每天增加一天，则增加3天。

示例查询如下所示，SQLFiddle is also available。

希望这可以解决您的问题。

with test_data as (
    SELECT 1 as id, 'A' as cd,to_date('10/01/2012','dd/mm/yyyy') as p_date, 10 as value, to_date('11/01/2012','dd/mm/yyyy') as some_other_date FROm DUAL UNION ALL 
    SELECT 1 as id, 'A' as cd,to_date('11/01/2012','dd/mm/yyyy') as p_date, 10 as value, to_date('12/01/2012','dd/mm/yyyy') as some_other_date FROm DUAL UNION ALL 
    SELECT 1 as id, 'A' as cd,to_date('12/01/2012','dd/mm/yyyy') as p_date, 9 as value, to_date('13/01/2012','dd/mm/yyyy') as some_other_date FROm DUAL UNION ALL 
    SELECT 1 as id, 'A' as cd,to_date('13/01/2012','dd/mm/yyyy') as p_date, 9 as value, to_date('14/01/2012','dd/mm/yyyy') as some_other_date FROm DUAL UNION ALL 
    SELECT 1 as id, 'A' as cd,to_date('16/01/2012','dd/mm/yyyy') as p_date, 9 as value, to_date('17/01/2012','dd/mm/yyyy') as some_other_date FROm DUAL UNION ALL 
    SELECT 1 as id, 'A' as cd,to_date('17/01/2012','dd/mm/yyyy') as p_date, 10 as value, to_date('18/01/2012','dd/mm/yyyy') as some_other_date FROm DUAL UNION ALL 
    SELECT 1 as id, 'A' as cd,to_date('18/01/2012','dd/mm/yyyy') as p_date, 10 as value, to_date('19/01/2012','dd/mm/yyyy') as some_other_date FROm DUAL 
) 
select 
    id, 
    cd, 
    value, 
    block_num, 
    min(p_date) as process_start_date, 
    max(p_date) as process_end_date 
from (
    select 
     id, 
     cd, 
     value, 
     p_date, 
     sum(is_block_start) over (partition by id, cd, value order by p_date) as block_num 
    from (
     select 
      id, 
      cd, 
      value, 
      p_date, 
      -- get end date of previous block  
      case when lag(case when to_char(p_date, 'DY') = 'FRI' then p_date+3 else p_date+1 end) 
      over (partition by id, cd, value order by p_date) = p_date then 0 else 1 end as is_block_start 
     from test_data 
     -- Make sure that the data definitely doesn't include Sat or Sun because this could just confuse things 
     where to_char(p_date, 'DY') not in ('SAT', 'SUN') 
    ) 
) 
group by id, cd, value, block_num 
order by id, cd, value, block_num