带有一个输出的多阵列

Question

这是我的代码，目前无法正常工作。我怎样才能使它工作？我的愿望是使输出像一个字符串（当然我知道如何“转换”数组是string）：

话改变，添加和删除，使之

代码：

<?php 

header('Content-Type: text/html; charset=utf-8'); 
$text = explode(" ", strip_tags("words altered added and removed to make it")); 
$stack = array(); 

$words = array("altered", "added", "something"); 
foreach($words as $keywords){ 
    $check = array_search($keywords, $text); 
    if($check>(-1)){ 
    $replace = " ".$text[$check].","; 
    $result = str_replace($text[$check], $replace, $text); 
    array_push($stack, $result); 
    } 
} 

print_r($stack); 
?> 

输出：

Array 
(
    [0] => Array 
     (
      [0] => words 
      [1] => altered, 
      [2] => added 
      [3] => and 
      [4] => removed 
      [5] => to 
      [6] => make 
      [7] => it 
     ) 

    [1] => Array 
     (
      [0] => words 
      [1] => altered 
      [2] => added, 
      [3] => and 
      [4] => removed 
      [5] => to 
      [6] => make 
      [7] => it 
     ) 
) 

Answer 1

没有更多的解释是这样简单：

$text = strip_tags("words altered added and removed to make it"); 
$words = array("altered", "added", "something"); 

$result = $text; 
foreach($words as $word) { 
    $result = str_replace($word, "$word,", $result); 
} 

• 不爆炸源字符串
• 循环的话，用这个词替换词，并添加逗号

或放弃循环方法：

$text = strip_tags("words altered added and removed to make it"); 
$words = array("altered", "added", "something"); 

$result = preg_replace('/('.implode('|', $words).')/', '$1,', $text); 

• 被爆在交替的话（OR）创建一个模式操作|
• 字$1和逗号替换找到的字

Answer 2

您可以使用iterator

// Array with your stuff. 
$array = []; 

$iterator = new RecursiveIteratorIterator(new RecursiveArrayIterator($array)); 
foreach($iterator as $value) { 
    echo $v, " "; 
} 

Answer 3

你原来的做法应该有一些修改工作。代之以循环展开字符串中的单词。对于每一个，如果它在要修改的单词数组中，请添加逗号。如果不是，不要。然后，修改后的（或不）字进入堆栈。

$text = explode(" ", strip_tags("words altered added and removed to make it")); 
$words = array("altered", "added", "something"); 

foreach ($text as $word) { 
    $stack[] = in_array($word, $words) ? "$word," : $word; 
}