我在Python中实现了一个简单的网络'游戏' - 服务器绘制一个随机数,然后客户端试图猜测它。我的应用程序工作得很好,当客户端猜测数字时,它会与服务器断开连接(它在客户端处理)。修改客户端线程的服务器变量(线程,python)
但是,经过适当的猜测后,数字仍然是一样的。我想修改应用程序,这样,当客户端猜测数字时,服务器应该随后为其添加一个新的数字,以便其他客户端可以猜出新的数字。我怎样才能做到这一点?
一些模板,只是画一个注意的问题:
#!/usr/bin/env python
from random import randint
import socket, select
from time import gmtime, strftime
import threading
import sys
class Handler(threading.Thread):
def __init__(self, connection, randomnumber):
threading.Thread.__init__(self)
self.connection = connection
self.randomnumber = randomnumber
def run(self):
while True:
try:
data = self.connection.recv(1024)
if data:
print data
try:
num = int(data)
if Server.guess(num) :
msg = "You won! This is the right number!"
self.connection.send(msg)
break
else :
msg = "Try again!"
self.connection.send(msg)
except ValueError, e:
msg = "%s" % e
self.connection.send(msg)
else:
msg = "error"
self.connection.send(msg)
except socket.error:
self.connection.close()
break
self.connection.close()
class Server:
def __init__(self, ip, port):
self.ip = ip
self.port = port
self.address = (self.ip, self.port)
self.server_socket = None
self.randnum = randint(1, 100)
@classmethod
def guess(cls, no):
if cls.randnum == no:
cls.randnum = randint(1, 1000)
result = True
else:
result = False
return reslut
def run(self):
try:
self.server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
self.server_socket.bind((self.ip, self.port))
self.server_socket.listen(10)
print 'Num is %s' % self.randnum
while True:
connection, (ip, port) = self.server_socket.accept()
c = Handler(connection, self.randnum)
c.start()
except socket.error, e:
if self.server_socket:
self.server_socket.close()
sys.exit(1)
if __name__ == '__main__':
s = Server('127.0.0.1', 1234)
s.run()
如果每个客户获得自己的随机数,它应该猜到,还是应该只有所有客户都会猜测一个随机数字? – shanmuga
@shanmuga:应该只有一个随机数,所有客户需要猜测。当一个客户猜测它时,该数字应该改变。 – yak