选择一个行匹配条件或第一个匹配条件，如果没有任何匹配条件

Question

我有一个包含一些数据的表。它看起来像：

MariaDB [lokatnik]> SELECT id_elixir, start_time FROM elixir ORDER BY start_time ASC; 
+-----------+------------+ 
| id_elixir | start_time | 
+-----------+------------+ 
|   3 | 00:00:00 | 
|   1 | 12:30:00 | 
|   2 | 13:30:00 | 
+-----------+------------+ 
3 rows in set (0.00 sec) 

现在，我需要选择具体哪一行匹配时间条件 - 说 - START_TIME> some_time。

例如：

• 当some_time是10:00，然后我需要id_elixir行= 1（首先用的时间比10:00多行），
• 当some_time是13:00 ，那么我需要一排id_elixir = 2（如上），
• 时some_time时间为14:00，然后我需要id_elixir ROW = 3

我怎样才能使用SQL此行（和MySQL/MariaDB DBMS）？

Answer 1

也许，这样的事情会为你工作：

SELECT 
    * 
FROM 
    elixir 
WHERE 
    CASE 
    WHEN start_time BETWEEN CAST('10:00:00' AS TIME) AND CAST('13:00:00' AS 
     TIME) 
    THEN id =1 
    WHEN start_time BETWEEN CAST('13:00:00' AS TIME) AND CAST('14:00:00' AS 
     TIME) 
    THEN id   =2 
    WHEN start_time > CAST('14:00:00' AS TIME) 
    THEN id   =3 
    ELSE true 

但实际上你可以检查，通过使用简单的布尔运算符：

SELECT 
    * 
FROM 
    elixir 
WHERE 
    (
    start_time BETWEEN CAST('10:00:00' AS TIME) AND CAST('13:00:00' AS TIME) 
    AND id =1 
) 
OR 
    (
    start_time BETWEEN CAST('13:00:00' AS TIME) AND CAST('14:00:00' AS TIME) 
    AND id =2 
) 
OR 
    (
    start_time > CAST('14:00:00' AS TIME) 
    AND id  =3