2015-12-25 102 views
0

我想创建一个字典列表,以便将其导出为CSV。正如你可能在PowerShell中所知道的那样,如果你想将一个填充了字符串的数组导出为CSV文件,它将不起作用,所以我必须为此创建对象。Powershell字典或哈希表的列表

但是我这样做的方式,如果回避,我不觉得这是创建一个字典/散列表的正确方式,但我没有创建一个函数重复的代码(对不起) 。

#add the log file. 
$savegrp = Get-Content "J:\savegrp.dec.2015.log" 
#filtering into a var just Succeeded/Failed data then replace space with ';' and remove ',' 
$succeded = ($savegrp -cmatch "Succeeded:") -replace "\s+",";" -replace ",","" 
$failed = ($savegrp -cmatch " Failed: ") -replace "\s+",";" -replace ",","" 

#creating container where all data will be added 
$container = @() 
#just a date to save the csv file if this script will be scheduled 
$date = Get-Date -format dd.MMMM.yyyy 

#take each line of data with 'Succeeded' match and iterate it 
for($i=0;$i -le ($succeded.count-1);$i++) { 

    #split each line by ';' to see how many items are per one line 
    $s1 = ($succeded[$i]).split(";") 

    #if in one 'Succeeded' line are just 6 element then is just one server which is ok 
    if ($s1.count -eq 6){ 

     $PropertyHash = @{} 
     $PropertyHash = @{ 
      "Date" = $s1[1] + " " + $s1[0] 
      "Time" = $s1[2] 
      "Client" = $s1[5] 
      "Status" = $s1[4].Substring(0,9) 
     } 
     $container += New-Object -TypeName PSObject -Property $PropertyHash 
    } 
    #if in one 'Succeeded' line are more servers, then stick all sererers to the same info in the line 
    else{ 
     $count = ($s1.count) 

     for($a = $count-1;$a -ge 5){ 

      $PropertyHash = @{} 
      $PropertyHash += @{ 
       "Date" = $s1[1] + " " + $s1[0] 
       "Time" = $s1[2] 
       "Client" = $s1[$a] 
       "Status" = $s1[4].Substring(0,9) 
      } 
      $container += New-Object -TypeName PSObject -Property $PropertyHash 
      $a-- 
     } 
    } 
} 
+0

是啊,我有5个元素,并线,5号线+ n个元素,所以我想要隔离 – Xao

+0

GetEnumerator()? $ PropertyHash = [PSCustomObject] @ {}? –

回答

1

像这样的东西应该工作得很好,只要你有PowerShell的V3或更新:

for ($i = 0; $i -lt $succeded.Count; $i++) { 
    $date1, $date2, $time, $null, $status, $clients = $succeded[$i].Split(';') 
    $clients | ForEach-Object { 
    New-Object -Type PSObject -Property @{ 
     'Date' = "$date2 $date1" 
     'Time' = $time 
     'Client' = $_ 
     'Status' = $status.Substring(0,9) 
    } 
    } | Export-Csv 'C:\path\to\output.csv' -NoType -Append 
} 

PowerShell允许数组分配给变量的列表,每一个从接受一个元素该数组除了最后一个,它接受所有剩余的数组元素。声明

$date1, $date2, $time, $null, $status, $clients = $succeded[$i].Split(';') 

收集日期,时间和状态的各个变量$date1$date2$time$status。通过将其分配给$null来丢弃第4个值。由分割操作(客户端列表)产生的数组的其余部分分配给“全部捕获”变量$clients。然后,您可以将该变量传送到ForEach-Object声明中,在该语句中为每个客户端创建一个对象并将它们附加到您的CSV文件(请注意,您至少需要PowerShell v3才能附加到CSV)。

编辑:如果您遇到PowerShell v2或更早的版本,您还可以在循环之外进行导出。然而,对于工作,你需要或者在一个子表达式运行它:

(for ($i = 0; $i -lt $succeded.Count; $i++) { 
    $date1, $date2, $time, $null, $status, $clients = $succeded[$i].Split(';') 
    $clients | ForEach-Object { 
    New-Object -Type PSObject -Property @{ 
     'Date' = "$date2 $date1" 
     'Time' = $time 
     'Client' = $_ 
     'Status' = $status.Substring(0,9) 
    } 
    } 
}) | Export-Csv 'C:\path\to\output.csv' -NoType 

或先收集在一个变量的结果:

$container = for ($i = 0; $i -lt $succeded.Count; $i++) { 
    $date1, $date2, $time, $null, $status, $clients = $succeded[$i].Split(';') 
    $clients | ForEach-Object { 
    New-Object -Type PSObject -Property @{ 
     'Date' = "$date2 $date1" 
     'Time' = $time 
     'Client' = $_ 
     'Status' = $status.Substring(0,9) 
    } 
    } 
} 

$container | Export-Csv 'C:\path\to\output.csv' -NoType 
+1

为什么不把''''输出到'Export-Csv'('&{for ...} | Export-Csv'),所以你不必追加? – PetSerAl

+1

@PetSerAl这将需要在子表达式或scriptblock中运行'for'循环,我试图避免这种情况,因为我觉得语法丑陋。一个scriptblock也会使'$ succeded'的处理稍微复杂一些。如果OP有PowerShell v2,我宁愿在一个变量('$ container = for(...){...}')中收集循环结果并将其导出为CSV。 –