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在Python中,使用异步请求,从并得到,我想打印来自async.map()如何从python 2.7的url上的async.get()打印JSON结果?
from requests import async
url_list = ['abc.com','xyz.com']
rs = [async.get(u) for u in url_list]
a = async.map(rs)
print a
响应这给我结果
[<Response[200]>,<Response[200]>]
我想打印从URL的感谢
什么是'async'? – wim
你目前得到了什么? – roganjosh
@roganjosh [,] –
Abhi