SQL SELECT查询逻辑，用2份

QUERY1

SELECT  r.userId, r.programmeId, u.email, u.firstName, u.lastName, u.profileId, tblProgrammes.name, u.storeId, r.dateEnded AS lastPass, r.dateExpired 
FROM   tblUserRepeatHistory AS r INNER JOIN 
         tblUsers AS u ON r.userId = u.id INNER JOIN 
         tblProgrammes ON r.programmeId = tblProgrammes.id 
WHERE  (u.storeId = @storeId) AND (r.userId = @userId) 
GROUP BY r.userId, r.programmeId, u.email, u.firstName, u.lastName, u.profileId, tblProgrammes.name, u.storeId, r.dateEnded, r.dateExpired 
HAVING  (DATEDIFF(D, MAX(r.dateExpired), GETDATE() + 31) >= 0)

与

QUERY2

SELECT TOP (1) r.id, p.maxSteps 
FROM tblUserQuestionnaireHistory AS r INNER JOIN 
tblProgrammes AS p ON r.programmeId = p.id AND r.stepId = p.maxSteps 
WHERE (r.userId = @UserId) AND (r.programmeId = @ProgrammeId) AND (r.success = 1) 
ORDER BY r.id DESC

的语法应该如下

从QUERY1连接QUERY2中选择全部QUERY2不记录任何记录。即如果QUERY2返回true总比不介意从QUERY1第一部分

SELECT * WHERE NOT EXISTS JOIN QUERY2其中@userId和@programmeId查询2来自QUERY1

来源

2011-06-16 StevieB

您不指定哪个**版本的SQL Server .....如果您使用的是SQL Server 2005或更新的版本，则可能需要使用[Common Table Expression（CTE ）]（http://www.simple-talk.com/sql/t-sql-programming/sql-server-cte-basics/）设置你的第一个选择，然后加入然后结果CTE提供给第二个选择你需要..... – 2011-06-16 10:47:05

你可以使用outer apply找到返回的记录top 1一排匹配您的条件：

select * 
from tblUserRepeatHistory u 
outer apply 
     (
     select top 1 * 
     from tblUserQuestionnaireHistory r 
     on  r.userId = u.UserId 
       and r.programmeId = u.programmeId 
       and r.success = 1 
       and r.stepId = 9 
     ) as r

来源

2011-06-16 10:46:43 Andomar

这是您的意思吗？

SELECT r.userId, r.programmeId, u.email, u.firstName, (SELECT TOP (1) r.id FROM tblUserQuestionnaireHistory AS r WHERE (r.userId = urh.UserId) AND (r.programmeId = urh.ProgrammeId) AND (r.success = 1) AND r.stepId = 9) 
FROM tblUserRepeatHistory urh 
where urh.UserId = @UserId and usr.ProgrammeId = @programmeId

来源

2011-06-16 10:47:23 JNappi

SQL SELECT查询逻辑，用2份

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