2014-10-09 68 views
0

只显示最后一项HashMap正在显示。 我的哈希映射由雇员类型的键和类型爱好的值组成,但只显示最后一个条目正在显示。HashMap只显示最后一项

请帮我在此代码删除错误:

public void addEmployees(int a, HashMap<Employee,Hobby> hMap) 
{ 
    Employee emp = new Employee(); 
    Hobby hob = new Hobby(); 
    Scanner obj = new Scanner(System.in); 
    Scanner obj1 = new Scanner(System.in); 

    for(int i =0; i<a ; i++) 
    { 
     System.out.println("Enter id of employee:"); 
     int num = obj.nextInt(); 
     emp.setEmployeeId(num); 

     System.out.println("Enter name of employee:"); 
     String str = obj1. nextLine(); 
     emp.setName(str); 

     hob.enterHobby(); 
     hMap.put(emp,hob); 
    }  
} 


public static void main(String [] args) 
{ 
    HashMap <Employee,Hobby> employeeName = new HashMap <Employee,Hobby>(); 
    System.out.println("Enter the number of employees you want to add"); 
    Scanner obj = new Scanner(System.in); 
    Scanner obj1 = new Scanner(System.in); 
    int num = obj.nextInt(); 
    EmployeeManag emg = new EmployeeManag(); 
    emg.addEmployees(num,employeeName); 
} 


class Hobby 
{ 
    ArrayList<String> arr = new ArrayList<String>(); 

    public void enterHobby() 
    { 
     Scanner obj1 = new Scanner(System.in); 
     System.out.println("Add Hobbie"); 
     String str = obj1.nextLine(); 
     arr.add(str); 
    } 

    public void displayHobbie() 
    { 
     for(String str : arr) 
     { 
      System.out.println(str); 
     } 
    } 
} 

class Employee 
{ 

    private int employeeId; 
    private String name; 

    public int getEmployeeId() 
    { 
     return employeeId; 
    } 
    public String getName() 
    { 
     return name; 
    } 
    public void setName(String name) 
    { 
     this.name = name; 
    } 

    public void setEmployeeId(int employeeId) 
    { 
     this.employeeId = employeeId; 
    } 
} 
+0

好像你不加入聘用过的员工向您传递给你的函数HashMap的,但其他一些哈希表 – Simon 2014-10-09 09:10:38

+0

你有没有被覆盖的'equals'和'hashCode'?如果没有,请了解他们的工作以及HashMap使用它们的方式。 – hyde 2014-10-09 09:10:59

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[Java HashMap“put”方法在for循环中可能重复](http://stackoverflow.com/questions/14671164/java-hashmap-put-method-in-a-for-loop) – Niroshan 2014-10-09 09:11:31

回答

3

创建内部for循环每次迭代EMP对象。

public void addEmployees(int a, HashMap<Employee,Hobby> aList) 
     { 
      Scanner obj = new Scanner(System.in); 
      Scanner obj1 = new Scanner(System.in); 

      for(int i =0; i<a ; i++) 
      { 
       Hobby hob = new Hobby(); 
       Employee emp = new Employee(); 
       System.out.println("Enter id of employee:"); 
       int num = obj.nextInt(); 
       emp.setEmployeeId(num); 

       System.out.println("Enter name of employee:"); 
       String str = obj1. nextLine(); 
       emp.setName(str); 

       hob.enterHobby(); 
       hMap.put(emp,hob); 
       }  
      } 
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你需要在循环中创建'Hobby',或者修改一个员工的爱好将会改变他们。 – Holloway 2014-10-09 09:14:22

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对不起,我错过了@Trengot – 2014-10-09 09:15:12