MYSQL：我如何删除第一行？

第一行是我的结果全部为空，我如何从结果中删除该结果？MYSQL：我如何删除第一行？

这是我的查询：

SELECT COALESCE(UNIX_TIMESTAMP(Date(p.published_at)),0) as 'day', 
     COALESCE(SUM(case when p.status = 2 then p.value end),0) as 'total_accepted', 
     COALESCE(SUM(case when p.status = 1 then p.value end),0) as 'total_open', 
     COALESCE(SUM(case when p.status = 3 then p.value end),0) as 'total_declined', 
     COALESCE(SUM(case when p.status !=0 then p.value end),0) as 'total_published' 
FROM posts as p 
GROUP BY DATE(p.published_at);

伊夫用于聚结从我结果的其余部分删除任何空值，所以第一行是技术上全部为0了。但我这个绘图数据，以及我行开始他们都在1970年...和计算机不存在当年= P

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2010-08-20 NullVoxPopuli

从您的问题描述，这应该解决这个问题：

SELECT COALESCE(UNIX_TIMESTAMP(Date(p.published_at)),0) as 'day', 
     COALESCE(SUM(case when p.status = 2 then p.value end),0) as 'total_accepted', 
     COALESCE(SUM(case when p.status = 1 then p.value end),0) as 'total_open', 
     COALESCE(SUM(case when p.status = 3 then p.value end),0) as 'total_declined', 
     COALESCE(SUM(case when p.status !=0 then p.value end),0) as 'total_published' 
FROM posts as p 
WHERE p.published_at IS NOT NULL 
GROUP BY DATE(p.published_at);

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2010-08-20 17:15:24

SELECT COALESCE(UNIX_TIMESTAMP(Date(p.published_at)),0) as 'day', 
     COALESCE(SUM(case when p.status = 2 then p.value end),0) as 'total_accepted', 
     COALESCE(SUM(case when p.status = 1 then p.value end),0) as 'total_open', 
     COALESCE(SUM(case when p.status = 3 then p.value end),0) as 'total_declined', 
     COALESCE(SUM(case when p.status !=0 then p.value end),0) as 'total_published' 
FROM posts as p 
WHERE 'day' <> 0 
GROUP BY DATE(p.published_at)

就过滤掉不需要的行。另一种方式来做到这将是

SELECT COALESCE(UNIX_TIMESTAMP(Date(p.published_at)),0) as 'day', 
     COALESCE(SUM(case when p.status = 2 then p.value end),0) as 'total_accepted', 
     COALESCE(SUM(case when p.status = 1 then p.value end),0) as 'total_open', 
     COALESCE(SUM(case when p.status = 3 then p.value end),0) as 'total_declined', 
     COALESCE(SUM(case when p.status !=0 then p.value end),0) as 'total_published' 
FROM posts as p 
WHERE p.published_at is not null 
GROUP BY DATE(p.published_at)

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2010-08-20 17:13:33 Frank

如果不止一个记录具有零作为'day'价值是什么？ – 2010-08-20 17:15:30

这应该不重要，因为它们在“GROUP BY”看到它们之前被过滤掉了。 – Frank 2010-08-20 17:23:43

您可以通过使用WHERE子句过滤掉包含所有空值行：

WHERE p.published_at IS NOT NULL AND p.status IS NOT NULL and p.value IS NOT NULL

添加此到查询给

SELECT COALESCE(UNIX_TIMESTAMP(Date(p.published_at)),0) as 'day', 
     COALESCE(SUM(case when p.status = 2 then p.value end),0) as 'total_accepted', 
     COALESCE(SUM(case when p.status = 1 then p.value end),0) as 'total_open', 
     COALESCE(SUM(case when p.status = 3 then p.value end),0) as 'total_declined', 
     COALESCE(SUM(case when p.status !=0 then p.value end),0) as 'total_published' 
FROM posts as p 
    WHERE p.published_at IS NOT NULL AND p.status IS NOT NULL and p.value IS NOT NULL 
GROUP BY DATE(p.published_at);

如果它是只需足以过滤NULL日期，然后使用

WHERE p.published_at IS NOT NULL

是你所需要的。一旦WHERE子句就位，日期上就不需要COALESCE，因为publish_at永远不会为空。

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2010-08-20 17:14:01 mdma

MYSQL：我如何删除第一行？

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