2015-02-09 23 views
3

我试图在使用built-in REST API创建的分析数据库上发出GET请求。当用户将文本输入到UISearchBar中时,将调用API调用,最终目标是在UITableView中显示返回的数据。下面的代码仅捕获我尝试创建一个有效的HTTP请求,其中我试图查看“Query1”是否与搜索字符串匹配(“Query1”是我的Parse数据库中的一个参数,基本上用作关联的搜索字词)。使用分析查询在Swift中调用REST API

//Mark - UISearchBarDelegate 

func searchBarSearchButtonClicked(searchBar: UISearchBar) { 
    makeRequest(searchBar.text) 
} 

func makeRequest (searchString : String) { 

    //REST API call to the sampleObjectData class 
    var request = NSMutableURLRequest(URL: NSURL(string: "https://api.parse.com/1/classes/sampleObjectData")!) 
    let session = NSURLSession.sharedSession() 
    request.HTTPMethod = "GET" 

    //THIS IS MY TROUBLE AREA 
    var params = urllib.urlencode({"where";:json.dumps({ 
     "Query1": "\(searchString)" 
     })}) 

    var error: NSError? 

    request.HTTPBody = NSJSONSerialization.dataWithJSONObject(params, options: nil, error: &error) 
    request.addValue("application/json", forHTTPHeaderField: "Content-Type") 
    //The kAppId & kRestAPIKey calls are referencing contstants at the top of the file 
    request.addValue("X-Parse-Application-Id", forHTTPHeaderField: kAppId) 
    request.addValue("X-Parse-REST-API-Key", forHTTPHeaderField: kRestAPIKey) 


    var task = session.dataTaskWithRequest(request, completionHandler: { (data, response, err) -> Void in 
     var stringData = NSString(data: data, encoding: NSUTF8StringEncoding) 
     println(stringData) 
    }) 
    task.resume() 
} 

结果是不会构建的代码,因为我无法弄清楚如何使用Swift将参数应用于Parse REST API。任何帮助,将不胜感激。

回答

10

我在其他地方得到了帮助,但想要发布给我的答案是任何有同样问题的人。以下是Swift中Parse REST API调用的一个示例,该调用使用了上面列出的相同参数。

func makeParseRequest(searchString: String) { 

     var request = NSMutableURLRequest() 
     request.HTTPMethod = "GET" 
     request.addValue(kAppId, forHTTPHeaderField: "X-Parse-Application-Id") 
     request.addValue(kRestAPIKey, forHTTPHeaderField: "X-Parse-REST-API-Key") 
     request.addValue("application/json", forHTTPHeaderField: "Content-Type") 
     request.addValue("application/json", forHTTPHeaderField: "Accept") 

     var params = ["Query1" : "\(searchString)"] 
     var error: NSError? 
     var paramsJSON = NSJSONSerialization.dataWithJSONObject(params, options: nil, error: &error) 
     var paramsJSONString = NSString(data: paramsJSON!, encoding: NSUTF8StringEncoding) 
     var whereClause = paramsJSONString?.stringByAddingPercentEscapesUsingEncoding(NSASCIIStringEncoding) 

     let urlString = "https://api.parse.com/1/classes/sampleObjectData" 
     var requestURL = NSURL(string: String(format: "%@?%@%@", urlString, "where=", whereClause!)) 

     request.URL = requestURL! 

     var task = NSURLSession.sharedSession().dataTaskWithRequest(request, completionHandler: { (data, response, err) -> Void in 
      var stringData = NSString(data: data, encoding: NSUTF8StringEncoding) 
      println(stringData) 
     }) 

     task.resume() 
    } 
+1

在iOS 9中,不建议使用'stringByAddingPercentEscapesUsingEncoding'。这相反:'stringByAddingPercentEncodingWithAllowedCharacters(.URLQueryAllowedCharacterSet())' – Joey 2015-09-28 06:45:13