我尝试使用包含在tweet文本中的指定关键字来查询指定用户的推文。这里是我的代码:使用Python和Tweepy查询Twitter状态
# Import Tweepy, sleep, credentials.py
import tweepy
from time import sleep
from credentials import *
# Access and authorize our Twitter credentials from credentials.py
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
api = tweepy.API(auth)
SCREEN_NAME = "BachelorABC"
KEYWORD = "TheBachelor"
def twtr2():
raw_tweets = tweepy.Cursor(api.search, q=KEYWORD, lang="en").items(50)
for tweet in raw_tweets:
if tweet['user']['screen_name'] == SCREEN_NAME:
print tweet
twtr2()
我得到如下错误信息:
Traceback (most recent call last):
File "test2.py", line 19, in <module>
twtr2()
File "test2.py", line 17, in twtr2
if tweet['user']['screen_name'] == SCREEN_NAME:
TypeError: 'Status' object has no attribute '__getitem__'
我GOOGLE了很多,想,也许我需要保存Twitter的JSON在Python第一,所以我尝试以下:
import tweepy, json
from time import sleep
from credentials import *
auth = tweepy.OAuthHandler(consumer_key, consumer_secret)
auth.set_access_token(access_token, access_token_secret)
api = tweepy.API(auth)
SCREEN_NAME = "BachelorABC"
KEYWORD = "TheBachelor"
raw_tweets = tweepy.Cursor(api.search, q=KEYWORD, lang="en").items(50)
for tweet in raw_tweets:
load_tweet = json.loads(tweet)
if load_tweet['user']['screen_name'] == SCREEN_NAME:
print tweet
但是,结果是可悲的:
Traceback (most recent call last):
File "test2.py", line 35, in <module>
load_tweet = json.loads(tweet)
File "C:\Python27\lib\json\__init__.py", line 339, in loads
return _default_decoder.decode(s)
File "C:\Python27\lib\json\decoder.py", line 364, in decode
obj, end = self.raw_decode(s, idx=_w(s, 0).end())
TypeError: expected string or buffer
有人知道我的代码有什么问题吗?你能帮我解决它吗?
提前致谢!
感谢您的时间@ethanchewy我正在寻找带有**指定** screen_name和关键字的推文。一般来说,你的回答是关于前20条推文。你有什么想法找到这些条件的推文吗? – Counter10000
@LinguisticsStudent看看位于这里的最后一个代码片段:https://github.com/tweepy/tweepy/blob/master/docs/code_snippet.rst。您可以将screen_names存储在列表中,然后在该列表中搜索某个screen_name。 请注意,Twitter对查询有严格的限制。 – ethanchewy
谢谢@ethanchewy。上面引用的页面是从追随者或用户检索screen_name,而不是状态。如果我稍后再找到答案,我会更新。 – Counter10000