1
Input File Path as argument to program
File Path : E:\TestCode\Test file space\abc.xml
Code : This code will accept the above file path as argument.
package com.org;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
public class FileSepratorTest {
public static void main(String[] args) {
String filePath = args[0]; // It will take file path as E:\TestCode\Test file space\abc.xml
try {
System.out.println("File Path :"+filePath); // printing file path
FileInputStream file = new FileInputStream(new File(filePath));
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}
Exception occurs when execute this code with space separated folder name
File Path :E:\TestCode\Test
java.io.FileNotFoundException:E:\ TestCode \测试(系统找不到指定的文件)
在java.io.FileInputStream.open (本机方法) 在java.io.FileInputStream中。(来源不明) 在com.org.FileSepratorTest.main(FileSepratorTest.java:16)从命令行执行Jar文件与文件夹名称空间
它没有显示整个文件路径,我知道我需要以此为参数,但我想执行jar文件,jar文件路径指定如下
E:\TestCode\executable_jar>java -cp E:\TestCode\executable_jar\abc_lib -jar redmas- migration.jar E:\TestCode\Migration Letest File\abc.xml** **in my application.
试一下:java -cp E:\ TestCode \ executable_jar \ abc_lib -jar redmas- migration.jar”E:\ TestCode \ Migration Letest File \ abc.xml“ – chf
使用双引号“路径”来包含路径 –
感谢您的帮助,它按预期工作。 –