有没有办法做一个职位在PHP

Question

我想做一个简单的职位到Facebook，我有同样的样本做一个邮政编码，我改变了一点。

我收到以下错误

解析错误：语法错误，意外 ';'在上线/home/consult/public_html/projects/facebook/index.php 13

线是

'access_token'=>;urlencode($code), 

的代码：

<?php 
//set POST variables 
$url = 'https://graph.facebook.com/arjun/feed'; 
$code="testing"; 
$message="Test"; 
$fields = array(
    'access_token'=>;urlencode($code), 
    'message'=>;urlencode($message), 
       ); 

//url-ify the data for the POST 
foreach($fields as $key=&gt;$value) { $fields_string .= $key.'='.$value.'&amp;'; } 
rtrim($fields_string,'&amp;'); 

//open connection 
$ch = curl_init(); 

//set the url, number of POST vars, POST data 
curl_setopt($ch,CURLOPT_URL,$url); 
curl_setopt($ch,CURLOPT_POST,count($fields)); 
curl_setopt($ch,CURLOPT_POSTFIELDS,$fields_string); 

//execute post 
// $result = curl_exec($ch); 

//close connection 
curl_close($ch); 


?> 

Answer 1

它应该是

'access_token'=>urlencode($code), 

不是

'access_token'=>;urlencode($code), 

也

'message'=>;urlencode($message), 

应该

'message'=>urlencode($message), 

也

key=> 

应该

key=>