我正在使用hackerrank.com API进行代码编译。因此,当用户与编译错误代码进入JSON响应是这样如何解析包含特殊字符的JSON字符串?
{
"result": {
"callback_url": "",
"censored_compile_message": "",
"codechecker_hash": "something",
"compile_command": "/usr/lib/jvm/java-7-sun/bin/javac -encoding UTF-8 -classpath '*:/usr/share/java/json-simple-1.1.1.jar:/usr/share/java/junixsocket.jar:/usr/share/java/abacus-util-jdk7.jar' AddNumbers.java 1> compile.err 2>&1",
"compilemessage": "AddNumbers.java:1: error: ';' expected\nimport java.util.Scanner; class AddNumbers { public static void main(String args[]) { int x, y, z Scanner in = new Scanner(System.in); x = in.nextInt(); y = in.nextInt(); z = x + y; System.out.println(z); } }\n ^\n1 error\n",
"error_code": 0,
"hash": "something",
"loopback": null,
"memory": null,
"message": null,
"response_s3_path": "something",
"result": 255,
"run_command": "",
"server": "something",
"signal": null,
"stderr": null,
"stdout": null,
"time": null
}
}
在这个JSON“compilemessage”包含特殊的转义字符像'' "" ;
等。因此,如何使人物保持原样解析这个字符串。
当我试图只用正常
jsonobject.getString解析( “compilemessage”)
然后把它转换成一些随机字符作为图片所示
请包括[mcve]。 – shmosel
请参阅此quurstion之前http://stackoverflow.com/questions/9069799/android-json-charset-utf-8-problems –
哪一个你用于解析? –