Spring MVC的3：java.lang.IllegalStateException

嗨有人能帮助我了解我是什么在下面的代码做错了，由于我正在此错误：Spring MVC的3：java.lang.IllegalStateException

Caused by: java.lang.IllegalStateException: Neither BindingResult nor plain target object for bean name 'user' available as request attribute 
    at org.springframework.web.servlet.support.BindStatus.<init>(BindStatus.java:141) 
    at org.springframework.web.servlet.tags.form.AbstractDataBoundFormElementTag.getBindStatus(AbstractDataBoundFormElementTag.java:174) 
    at org.springframework.web.servlet.tags.form.AbstractDataBoundFormElementTag.getPropertyPath(AbstractDataBoundFormElementTag.java:194) 
    at org.springframework.web.servlet.tags.form.AbstractDataBoundFormElementTag.getName(AbstractDataBoundFormElementTag.java:160) 
    at org.springframework.web.servlet.tags.form.AbstractDataBoundFormElementTag.autogenerateId(AbstractDataBoundFormElementTag.java:147) 
    at org.springframework.web.servlet.tags.form.AbstractDataBoundFormElementTag.resolveId(AbstractDataBoundFormElementTag.java:138) 
    at org.springframework.web.servlet.tags.form.AbstractDataBoundFormElementTag.writeDefaultAttributes(AbstractDataBoundFormElementTag.java:122) 
    at org.springframework.web.servlet.tags.form.AbstractHtmlElementTag.writeDefaultAttributes(AbstractHtmlElementTag.java:408) 
    at org.springframework.web.servlet.tags.form.InputTag.writeTagContent(InputTag.java:140) 
    at org.springframework.web.servlet.tags.form.AbstractFormTag.doStartTagInternal(AbstractFormTag.java:102) 
    at org.springframework.web.servlet.tags.RequestContextAwareTag.doStartTag(RequestContextAwareTag.java:79) 
    at org.apache.jsp.WEB_002dINF.views.signUp_jsp._jspx_meth_form_005finput_005f0(signUp_jsp.java:179) 
    at org.apache.jsp.WEB_002dINF.views.signUp_jsp._jspx_meth_form_005fform_005f0(signUp_jsp.java:111) 
    at org.apache.jsp.WEB_002dINF.views.signUp_jsp._jspService(signUp_jsp.java:74) 
    at org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70) 
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:717) 
    at org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:374) 
    ... 59 more

UserManagementController.java

@Controller 
public class UserManagementController { 
    //displays sign up page(GET) 
    @RequestMapping(method=RequestMethod.GET, value="/signUp.html") 
    public ModelAndView signUpForm() { 
     System.out.println("Sign up"); 
     return new ModelAndView("/signUp", "user", new User()); 
    } 

}

signUp.jsp

<body> 
    <h3>Sign up</h3> 
    <table> 
     <form:form commandName="user" > 
      <tr> 
       <td>First name:</td> 
       <td><form:input path="firstName"/></td> 
      </tr> 
      <tr> 
       <td>Last name:</td> 
       <td><form:input path="lastName"/></td> 
      </tr> 
      <tr> 
       <td>Username:</td> 
       <td><form:input path="username"/></td> 
      </tr> 
      <tr> 
       <td>Password:</td> 
       <td><form:input path="password"/></td> 
      </tr> 
      <tr> 
       <td>Email:</td> 
       <td><form:input path="email"/></td> 
      </tr> 
      <tr> 
       <td></td> 
       <td><input type="submit" value="Submit"></td> 
      </tr> 
     </form:form> 
    </table> 
</body>

有人能帮我理解吗？

谢谢。

来源

2011-05-19 skip

你可以检查当JSP呈现，如果确实存在所谓的'user'请求属性？（例如，使用''） – Bozho 2011-05-19 17:47:54

@Bozho：我有一个propery'private boolean enabled = true;'，它有一个getter方法，用于我在此处用作用户域对象的用户域对象。当我尝试在'signUp.jsp'上检索'$ {user.enabled}'时，它没有显示任何内容，所以我认为确实没有'user'可用作请求属性。我不明白为什么？ – skip 2011-05-19 21:57:26

@Bozho：我能够显示'signUp.jsp'来测试'$ {user.enabled}'，因为我已经注释了完整的'

'元素，其中有''标签。 – skip 2011-05-19 22:07:58

回答

我错误地使用了错误的导入ModelAndView。我本来应该使用org.springframework.web.servlet.ModelAndView，但我错误地使用的是org.springframework.web.portlet.ModelAndView。

我现在有代码工作。

谢谢:)

来源

2011-05-20 03:45:28 skip

+1自己解决。如果可以，请接受你自己的答案。 – andyb 2011-05-20 13:36:14

@andyb：谢谢:)。直到接下来的19个小时才能接受它:) – skip 2011-05-20 21:59:22

Spring MVC的3：java.lang.IllegalStateException

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