我是全新的android开发和stackoverflow,所以请在我身上轻松一点。 ;)当使用TextView预期字符串时返回的Int int
我已经创建了一个包含多个TextView的ViewGroup。其中一个特别有一个switch case,其中case常量是在我的java对象中定义的整数。然后,我将case语句设置为我认为是String的值。最后,我使用setText()方法将TextView对象设置为此String。我遇到的问题是,实际返回到视图的是与案例相关的整数,而不是文本值。这使我相信,我传递给TextView的是一个整数,但我不知道如何或在哪里可以纠正这一点。
任何帮助将不胜感激。
的ViewGroup中的代码是在这里:
public View getView (int position, View convertView, ViewGroup parent)
{
ViewGroup listItem;
if (convertView == null) {
listItem = (ViewGroup) getLayoutInflator().inflate(R.layout.list_item, null);
}
else {
listItem = (ViewGroup) convertView;
}
MovieInfo movieInfo = list.get(position);
TextView movietitleText = (TextView) listItem.findViewById(R.id.movietitle_text);
TextView directorText = (TextView) listItem.findViewById(R.id.director_text);
TextView producerText = (TextView) listItem.findViewById(R.id.producer_text);
TextView releaseyearText = (TextView) listItem.findViewById(R.id.releaseyear_text);
TextView genreText = (TextView) listItem.findViewById(R.id.genre_text);
movietitleText.setText(movieInfo.getMovietitle());
producerText.setText(movieInfo.getProducer());
directorText.setText(movieInfo.getDirector());
releaseyearText.setText(movieInfo.getReleaseyear());
String genreName;
Resources resources = context.getResources();
switch (movieInfo.getGenre()) {
case MovieInfo.GENRE_ACTION:
genreName = resources.getString(R.string.action_label);
break;
case MovieInfo.GENRE_COMEDY:
genreName = resources.getString(R.string.comedy_label);
break;
case MovieInfo.GENRE_DRAMA:
genreName = resources.getString(R.string.drama_label);
break;
case MovieInfo.GENRE_FAMILY:
genreName = resources.getString(R.string.family_label);
break;
case MovieInfo.GENRE_HORROR:
genreName = resources.getString(R.string.horror_label);
break;
case MovieInfo.GENRE_ROMANCE:
genreName = resources.getString(R.string.romance_label);
break;
default:
case MovieInfo.GENRE_UNKNOWN:
genreName = resources.getString(R.string.unknown_label);
break;
}
genreText.setText(genreName);
return listItem;
}
常量在我的Java对象,这里定义的情况下:
public static final int GENRE_UNKNOWN = 0;
public static final int GENRE_ACTION = 1;
public static final int GENRE_COMEDY = 2;
public static final int GENRE_DRAMA = 3;
public static final int GENRE_FAMILY = 4;
public static final int GENRE_HORROR = 5;
public static final int GENRE_ROMANCE = 6;
private String movietitle;
private String director;
private String producer;
private String releaseyear;
private int genre;
,并设置类型的行动时,被选中的复选框中主要活动在这里:
if (actionCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_ACTION);
if (comedyCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_COMEDY);
if (dramaCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_DRAMA);
if (familyCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_FAMILY);
if (horrorCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_HORROR);
if (romanceCheckBox.isChecked()) movieInfo.setGenre(MovieInfo.GENRE_ROMANCE);
部分Strings.xml在这里:
<string name="movietitle_label">Movie Title</string>
<string name="director_label">Director</string>
<string name="producer_label">Producer</string>
<string name="releaseyear_label">Release Year</string>
<string name="genre_label">Genre</string>
<string name="action_label">Action</string>
<string name="comedy_label">Comedy</string>
<string name="drama_label">Drama</string>
<string name="family_label">Family</string>
<string name="horror_label">Horror</string>
<string name="romance_label">Romance</string>
<string name="unknown_label">Unknown</string>
<string name="ok_label">OK</string>
<string name="clear_label">Clear</string>
<string name="showdatabase_label">Show Database</string>
<string name="id_label">ID</string>
<string name="select">Select Year</string>
感谢您的帮助!
我会检查你的资源文件,看看是否例如R.string.action_label确实是一个字符串,而不是一个数字。 – Marcelo
您可以粘贴上面放置的R.string的strings.xml吗? (R.string.action_label等) –
Marcelo,R.string.action_label其实是一个int(public static final int action_label = 0x ####),但在我的Strings.xml文件中,我有动作 。由于R是自动生成的并且action_label已经在我的xml中定义为一个字符串,所以我如何让R识别它呢? –
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