SQL计数和SUM

Question

我有这个 表的表done_by

Var_ID| Var_name| Q1_by |Q2_by|Q3_by|Q4_by 
1  | abc | me | me |me |you 
2  | cba | me | me |you |you 
3  | abd | me | you |you |me 

的结果，我想的就是让所有的总我的所有 ，并且重视 我= 7 你= 5

做了计数，但我不能得到的是计数所有的“我”为每列

Answer 1

你可以有条件汇聚喜欢做的事：

SELECT SUM(CASE WHEN Q1_by = 'me' THEN 1 ELSE 0 END + 
      CASE WHEN Q2_by = 'me' THEN 1 ELSE 0 END + 
      CASE WHEN Q3_by = 'me' THEN 1 ELSE 0 END + 
      CASE WHEN Q4_by = 'me' THEN 1 ELSE 0 END) AS me , 
     SUM(CASE WHEN Q1_by = 'you' THEN 1 ELSE 0 END + 
      CASE WHEN Q2_by = 'you' THEN 1 ELSE 0 END + 
      CASE WHEN Q3_by = 'you' THEN 1 ELSE 0 END + 
      CASE WHEN Q4_by = 'you' THEN 1 ELSE 0 END) AS you 
FROM TableName 

Answer 2

使用每季度个别情况，并将它们添加

SELECT (
(SELECT Count(Q1_by) FROM done_by WHERE Q1_by = 'me')+ 
(SELECT Count(Q2_by) FROM done_by WHERE Q2_by = 'me')+ 
(SELECT Count(Q3_by) FROM done_by WHERE Q3_by = 'me')+ 
(SELECT Count(Q4_by) FROM done_by WHERE Q4_by = 'me')) AS MeCount, 
(
(SELECT Count(Q1_by) FROM done_by WHERE Q1_by = 'you')+ 
(SELECT Count(Q2_by) FROM done_by WHERE Q2_by = 'you')+ 
(SELECT Count(Q3_by) FROM done_by WHERE Q3_by = 'you')+ 
(SELECT Count(Q4_by) FROM done_by WHERE Q4_by = 'you')) AS YouCount 
FROM done_by 

IDEONE链接：使用“求和”，而不是“计数” https://ideone.com/ZAuS5O

Answer 3

有条件的聚集体的路要走，你可以扩展它使用动态SQL，如果你不知道不同的值 -

--Dynamic SQL Extension to count sum of all distinct values 
--Extract out distinct values in temporary table 
SELECT DISTINCT by_val=val INTO #by_tbl FROM (SELECT val=Q1_by 
FROM #TableName 
UNION ALL 
SELECT val=Q2_by 
FROM #TableName 
UNION ALL 
SELECT val=Q3_by 
FROM #TableName 
UNION ALL 
SELECT val=Q4_by 
FROM #TableName) A 


--Create a SQL String 
DECLARE @sql NVARCHAR(max) 

SELECT @sql = ISNULL(@sql+',', 'SELECT ') + '['+by_val+']=SUM(CASE WHEN Q1_by='''+by_val+''' THEN 1 ELSE 0 END 
       + CASE WHEN Q2_by='''+by_val+''' THEN 1 ELSE 0 END 
       + CASE WHEN Q3_by='''+by_val+''' THEN 1 ELSE 0 END 
       + CASE WHEN Q4_by='''+by_val+''' THEN 1 ELSE 0 END) ' 

FROM #by_tbl 

SET @sql = @sql + ' FROM #TableName' 

EXEC(@SQL) 


DROP TABLE #TableName 
DROP TABLE #by_tbl 

Answer 4

DECLARE @byMe INT = 0; 

SELECT @byMe = @byMe + COUNT(*) FROM dbo.tablName 
WHERE Q1_by = 'me'; 

SELECT @byMe = @byMe + COUNT(*) FROM dbo.tablName 
WHERE Q2_by = 'me'; 

SELECT @byMe = @byMe + COUNT(*) FROM dbo.tablName 
WHERE Q3_by = 'me'; 

SELECT @byMe = @byMe + COUNT(*) FROM dbo.tablName 
WHERE Q4_by = 'me'; 

SET @byMe = @byMe * 7;