问题在打印输出

-1

我使用下面的代码打印的MP2文件的ID3标签，但输出以这种形式问题在打印输出

Array ([FileName] => 4.mp3 [TAG] => ID3 [Version] => 3.0 [Title] => &Bahut Khubsurat Ghazal (mr-Jatt.Com) [Album] => 1Loverz Choice (A Khubsurat Ghazal) (www.mzc.in) [Author] => DJ Badboy (mr-Jatt.Com) [Track] => (www.mzc.in))

快到了，但我想简单的输出这样

文件名4 .mp3标题Bahut Khubsurat Ghazal（mr-Jatt.Com）专辑1Loverz Choice（A Khubsurat Ghazal）（www.mzc.in）作者DJ Badboy（mr-Jatt.Com）Track（www.mzc.in）

我的代码是

print_r(tagReader("4.mp3")); 
// ------------------------------ 
function tagReader($file) { 
    $id3v23 = array("TIT2","TALB","TPE1","TRCK","TDRC","TLEN","USLT"); 
    $id3v22 = array("TT2","TAL","TP1","TRK","TYE","TLE","ULT"); 
    $fsize = filesize($file); 
    $fd = fopen($file, "r"); 
    $tag = fread($fd, $fsize); 
    $tmp = ""; 
    fclose($fd); 
    if (substr($tag, 0, 3) == "ID3") { 
     $result['FileName'] = $file; 
     $result['TAG'] = substr($tag, 0, 3); 
     $result['Version'] = hexdec(bin2hex(substr($tag, 3, 1))) . "." . hexdec(bin2hex(substr($tag, 4, 1))); 
    } 
    if ($result['Version'] == "4.0" || $result['Version'] == "3.0") { 
     for($i = 0; $i < count($id3v23); $i ++) { 
      if (strpos($tag, $id3v23[$i] . chr(0)) != FALSE) { 
       $pos = strpos($tag, $id3v23[$i] . chr(0)); 
       $len = hexdec(bin2hex(substr($tag, ($pos + 5), 3))); 
       $data = substr($tag, $pos, 9 + $len); 
       for($a = 0; $a < strlen($data); $a ++) { 
        $char = substr($data, $a, 1); 
        if ($char >= " " && $char <= "~") 
         $tmp .= $char; 
       } 
       if (substr($tmp, 0, 4) == "TIT2") 
        $result['Title'] = substr($tmp, 4); 
       if (substr($tmp, 0, 4) == "TALB") 
        $result['Album'] = substr($tmp, 4); 
       if (substr($tmp, 0, 4) == "TPE1") 
        $result['Author'] = substr($tmp, 4); 
       if (substr($tmp, 0, 4) == "TRCK") 
        $result['Track'] = substr($tmp, 4); 
       if (substr($tmp, 0, 4) == "TDRC") 
        $result['Year'] = substr($tmp, 4); 
       if (substr($tmp, 0, 4) == "TLEN") 
        $result['Lenght'] = substr($tmp, 4); 
       if (substr($tmp, 0, 4) == "USLT") 
        $result['Lyric'] = substr($tmp, 7); 
       $tmp = ""; 
      } 
     } 
    } 
    if ($result['Version'] == "2.0") { 
     for($i = 0; $i < count($id3v22); $i ++) { 
      if (strpos($tag, $id3v22[$i] . chr(0)) != FALSE) { 
       $pos = strpos($tag, $id3v22[$i] . chr(0)); 
       $len = hexdec(bin2hex(substr($tag, ($pos + 3), 3))); 
       $data = substr($tag, $pos, 6 + $len); 
       for($a = 0; $a < strlen($data); $a ++) { 
        $char = substr($data, $a, 1); 
        if ($char >= " " && $char <= "~") 
         $tmp .= $char; 
       } 
       if (substr($tmp, 0, 3) == "TT2") 
        $result['Title'] = substr($tmp, 3); 
       if (substr($tmp, 0, 3) == "TAL") 
        $result['Album'] = substr($tmp, 3); 
       if (substr($tmp, 0, 3) == "TP1") 
        $result['Author'] = substr($tmp, 3); 
       if (substr($tmp, 0, 3) == "TRK") 
        $result['Track'] = substr($tmp, 3); 
       if (substr($tmp, 0, 3) == "TYE") 
        $result['Year'] = substr($tmp, 3); 
       if (substr($tmp, 0, 3) == "TLE") 
        $result['Lenght'] = substr($tmp, 3); 
       if (substr($tmp, 0, 3) == "ULT") 
        $result['Lyric'] = substr($tmp, 6); 
       $tmp = ""; 
      } 
     } 
    } 
    return $result; 
}

来源

2012-10-12 payal

您可以尝试

foreach (tagReader("4.mp3") as $name => $value) { 
    printf("<p>%s:%s</p>", $name, $value); 
}

来源

2012-10-12 16:02:02 Baba

感谢它的工作 – payal

@payal欢迎你.. .. :) – Baba

这是因为你正在返回一个数组。如果你想打印出数组元素的内容，你将不得不遍历数组并打印每个元素，而不是返回整个数组。

喜欢的东西：

foreach ($results as $key => $value) 
    echo $key . " " . $value;

来源

2012-10-12 15:59:36 Jim

可以请你建议如何实现这一 – payal

@payal - 看到修改后的答案 – Jim

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