Python的映射类型的字典

假设我有一些含字典个月，短的名字和一些数据Python的映射类型的字典

data_in = {"Jan":2.0, "Feb":5.5}

和一些类型的字典包含映射

month_names = {"Jan":"January", "Feb":"February"} 
day_month = {day:"Jan" for day in range(1,32)} 
day_month.update({day:"Feb" for day in range(32,60)})

我如何获得包含与原始数据如下字典长名称和天数作为元组？

{("January", 1):2.0, ("January", 2):2.0 ...}

来源

2017-03-01 jebob

注意'update'修改字典，但返回'None'。所以'day_month = {...}。update（...）'使'day_month'等于'None'。 – unutbu

你的'update'缺少结尾'）' – depperm

@depperm不用介意其他无效的语法，对吧？ :) –

继承人我自己尝试 -

from itertools import count 
c = count(1,1) 
days = {"Feb" : 28, "Jan" : 31} 

mapping = {(month_names[i], next(c)) : data_in[i] for i in data_in.keys() for _ in range(days[i])} 

print (mapping)

或使用day_month字典

mapping = {(month_names[day_month[i]], i) : data_in[day_month[i]] for i in day_month.keys()} 

print mapping

输出 -

{('January', 1): 2.0, 
('January', 2): 2.0, 
('January', 3): 2.0, 
('January', 4): 2.0, 
('January', 5): 2.0, 
('January', 6): 2.0, 
('January', 7): 2.0, 
('January', 8): 2.0, 
('January', 9): 2.0, 
('January', 10): 2.0, 
('January', 11): 2.0, 
('January', 12): 2.0, 
('January', 13): 2.0, 
('January', 14): 2.0, 
('January', 15): 2.0, 
('January', 16): 2.0, 
('January', 17): 2.0, 
('January', 18): 2.0, 
('January', 19): 2.0, 
('January', 20): 2.0, 
('January', 21): 2.0, 
('January', 22): 2.0, 
('January', 23): 2.0, 
('January', 24): 2.0, 
    ..... }

来源

2017-03-01 19:15:15 hashcode55

好像你想要做的就是遍历day_month字典的键是什么，并为每个需要从month_names和data_in值匹配的条目，所以它应该是这个样子：

result = {} 
for day in day_month.keys(): 
    short_month = day_month[day] 
    data = data_in[short_month] 
    name = month_names[short_month] 
    new_key = (name, day) 
    result[new_key] = data

来源

2017-03-01 19:01:41 MByD

这不运行 – depperm

@depperm - 谨慎详细说明？ – MByD

把这个放在他的代码后面，它给出错误'AttributeError：'NoneType'对象没有'keys''属性 – depperm

Python的映射类型的字典

回答

相关问题