转换和格式列表，元组

-5

c = [ 
[ 
    [ 
    [670515.231, 6577538.931, 51.703], 
    [670486.853, 6577531.536, 51.703], 
    [670488.927, 6577523.577, 51.703], 
    [670517.305, 6577530.971, 51.703], 
    [670515.231, 6577538.931, 51.703] 
    ] 
] 
]

而且我想/格式转换到阵列的一个元组：S：

new_c =(
    [670515.231, 6577538.931, 51.703], 
    [670486.853, 6577531.536, 51.703], 
    [670488.927, 6577523.577, 51.703], 
    [670517.305, 6577530.971, 51.703], 
    [670515.231, 6577538.931, 51.703])

这样做的最佳方法是什么？

来源

2017-06-12 SHUMAcupcake

你想'元组（C [0] [0] ）'？ – ozgur

只是为了澄清：从技术上讲，这些列表不是数组。 :) – MSeifert

>>> c = [ 
... [ 
... [ 
...  [670515.231, 6577538.931, 51.703], 
...  [670486.853, 6577531.536, 51.703], 
...  [670488.927, 6577523.577, 51.703], 
...  [670517.305, 6577530.971, 51.703], 
...  [670515.231, 6577538.931, 51.703] 
... ] 
... ] 
... ] 

>>> new_c = tuple(c[0][0]) 

>>> pprint(new_c) 
([670515.231, 6577538.931, 51.703], 
[670486.853, 6577531.536, 51.703], 
[670488.927, 6577523.577, 51.703], 
[670517.305, 6577530.971, 51.703], 
[670515.231, 6577538.931, 51.703])

来源

2017-06-12 12:45:55 Uriel

你可以这样做：

c_tuple = tuple(c[0][0])

如果列表中的嵌套深度是每个情况不同：

tmp = c 
while len(tmp) == 1: 
    tmp = tmp[0] 

c_tuple = tuple(tmp)

来源

2017-06-12 12:48:36

转换和格式列表，元组

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