2017-01-10 51 views
0

我正在使用slim-framework v2和php来获取json outputs.With这段代码,我得到了关于该主题描述的错误。 MySQL表格格式不正确,现在无法更改,所以我以这种方式制作这些功能,因为我不是很有经验。 解决这个问题的最好方法是什么?如果可以用sql命令完成,会更好,所以我可以从主循环中删除这些函数吗?循环中的函数是否坏? ps:让我知道如果主题看起来不对。错误:PDO类的对象无法转换为字符串

测试()是客户ID

function test($server, $user, $pass, $db) { 
    $result = array(); 
    $sql = "SELECT cid from tasks where total!=0"; 
    $db = newDB($server, $user, $pass, $db); 
    $stmt = $db->prepare($sql); 
    $stmt->execute(); 
    foreach ($stmt as $v) { 
    $result[] = ['cid'=> $v['cid'], 'test'=> toGet($server, $user, $pass, $db, $v['cid']), 'test2'=> toGet2($server, $user, $pass, $db, $v['cid'])]; 
    } 
    echo json_encode($result, JSON_FORCE_OBJECT); 
} 

和其他功能

function toGet($server, $user, $pass, $db, $id) { 
    $sql = "SELECT sum(`poso`) as posoe from `economics` where `custid`=:id and flag=0"; 
    $db = newDB($server, $user, $pass, $db); 
    $stmt = $db->prepare($sql); 
    $stmt->bindParam("id", $id); 
    $stmt->execute(); 
    $row = $stmt->fetch(PDO::FETCH_NUM); 
    return $row[0]; 
} 

function toGet2($server, $user, $pass, $db, $id) { 
    $sql = "SELECT sum(`poso`) as posoe from `economics` where `custid`=:id and flag=1"; 
    $db = newDB($server, $user, $pass, $db); 
    $stmt = $db->prepare($sql); 
    $stmt->bindParam("id", $id); 
    $stmt->execute(); 
    $row = $stmt->fetch(PDO::FETCH_NUM); 
    return $row[0]; 
} 

非常感谢你的主循环!

UPDATE: 打开调试$ APP->配置( '调试',真正的),终于得到了错误 类型:ErrorException 代码:4096 消息:类PDO的对象无法转换为字符串 文件:/var/www/api/newdb.php 线:6

function newDB($host, $user, $pass, $db) { 
    $dbhost= $host; 
    $dbuser= $user; 
    $dbpass= $pass; 
    $dbname= $db; 
    $dbConnection = new PDO("mysql:host=$dbhost;dbname=$dbname", $dbuser, $dbpass); 
    $dbConnection->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); 
    $dbConnection->query('set names utf8'); 
    return $dbConnection; 
} 

UPDATE2:修身的conf

include 'newdb.php'; 
require 'Slim/Slim.php'; 
\Slim\Slim::registerAutoloader(); 
$app = new \Slim\Slim(); 
$app->config('debug', true); 
$app->response->setStatus(200); 
$app->contentType('application/json; charset=utf-8'); 
$app->get('/test/:server/:user/:pass/:db', 'test'); 
$app->get('/', function() use($app) { 
    $app->response->setStatus(200); 
    echo "Welcome!"; 
}); 
$app->run(); 
+0

嗯......什么行生成该错误获取数据? – AbraCadaver

+0

这是第6行,我的问题已更新 – UrL

回答

0

该问题可以通过Freenode上的一个人的单个MYSQL查询来解决。

- Reconnecting on db for each query was bad. 
- toGet() toGet2() removed 

我可以用单查询

SELECT t1.custid as cid, sum(if(t2.flag=0,t2.poso,0)) as posoX, 
sum(if(t2.flag=1,t2.poso,0)) as posoY from tasks t1 
left join economics t2 on t2.custid=t1.custid and t2.flag in (0,1) group by t1.custid; 
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