MYSQL - 函数不返回预期结果

Question

我正在构建一个网站的房地产租金。我现在正在进行搜索，我试图设置一个函数，我可以为每个属性调用。该功能需要抓取连接到给定属性的rental_periods表中的所有行，然后计算出最佳（最便宜）的每周价格。

我已经设置了下列表格。多行每个属性，与ID并列 -

properties - 每个属性

rental_periods一行。

每行是selfcatered或catered。 wdpd

WeekEndPerNight - - wepn

每月价格 - monthly

周价格 - wk

• WeekDayPerDay：

  如果selfcatered价格需要在给定的价格来制定

  如果catered价格可以在给定的：

  • PerPersonPerNight - pppn
  • PerNight - pn
  • PerPersonPerWeek - pppw

  我需要一个函数，它接受一个属性ID，然后抓住各个时期那么这取决于自己承担/照顾的每周最好的价格。

  我到目前为止似乎没有工作。它要么返回NULL或返回100000.00（我的上限默认价格）。

  下面的代码

  DELIMITER $$ 
  
  
  CREATE FUNCTION get_price(myid INT) 
      RETURNS VARCHAR(20) 
  
  BEGIN 
      DECLARE done INT DEFAULT 0; 
      DECLARE price decimal(30,3) default 100000.000; 
  
      DECLARE id INT; 
      DECLARE prop_id INT; 
      DECLARE type enum('catered','selfcatered'); 
      DECLARE name varchar(45); 
  
      DECLARE `from` date; 
      DECLARE `to` date; 
  
      DECLARE currency varchar(45); 
      DECLARE so tinyint; 
      DECLARE wk decimal(30,3); 
      DECLARE wepn decimal(30,3); 
  
      DECLARE wdpd decimal(30,3); 
      DECLARE monthly decimal(30,3); 
      DECLARE extra decimal(30,3); 
      DECLARE pppn decimal(30,3); 
      DECLARE pn decimal(30,3); 
  
      DECLARE pppw decimal(30,3); 
      DECLARE minstay int; 
      DECLARE maxstay int; 
      DECLARE breakfast varchar(45); 
      DECLARE annual TINYINT; 
  
      DECLARE cur1 CURSOR FOR SELECT * FROM rental_periods WHERE prop_id = myid; 
  
      DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; 
  
      OPEN cur1; 
  
      REPEAT 
      FETCH cur1 INTO id, prop_id, type, name, `from`, `to`, currency, so, wk, wepn, wdpd, minstay, maxstay, monthly, extra, pppn, pn, pppw, breakfast, annual; 
  
      IF NOT done THEN 
       IF (@type = "selfcatered") THEN 
        IF (@wdpd > 0 AND (@wdpd * 7) < @price) THEN 
         SET price = @wdpd * 7; 
        END IF; 
  
        IF (@wepn > 0 AND (@wepn * 7) < @price) THEN 
         SET price = @wepn * 7; 
        END IF; 
  
        IF ((@wdpd > 0 AND @wepn > 0) AND 
        (@wdpd * 5 + @wepn * 2) < @price) THEN 
         SET price = @wdpd * 5 + @wepn * 2; 
        END IF; 
  
        IF (@monthly > 0 AND (@monthly/(52/12)) < @price) THEN 
         SET price = @monthly/(52/12); 
        END IF; 
  
        IF (@wk > 0 AND @wk < @price) THEN 
         SET price = @wk; 
        END IF; 
       ELSE 
        IF (@pppn > 0 AND (@pppn * 7) < @price) THEN 
         SET price = @pppn * 7; 
        END IF; 
  
        IF (@pn > 0 AND (@pn * 7) < @price) THEN 
         SET price = @pn * 7; 
        END IF; 
  
        IF (@pppw > 0 AND (@pppw) < @price) THEN 
         SET price = @pppw; 
        END IF; 
       END IF; 
      END IF; 
      UNTIL done END REPEAT; 
  
      CLOSE cur1; 
  
      RETURN price; 
  END $$ 
  

  我希望/不完蛋了与我怎么安排的呢，还是我缺乏纯粹的MySQL的一些愚蠢的事。

  任何帮助将是非常有帮助的。

  编辑：

  下面是rental_periods为例行：

  INSERT INTO `rental_periods` (`id`, `prop_id`, `type`, `name`, `from`, `to`, `currency`, `so`, `wk`, `wepn`, `wdpd`, `minstay`, `maxstay`, `monthly`, `extra`, `pppn`, `pn`, `pppw`, `breakfast`, `annual`) 
  VALUES (64732, 32, 'selfcatered', 'Summer', '2012-06-01', '2012-08-31', NULL, 1, '350', '60', '100', '', '', '', '', NULL, NULL, NULL, NULL, 0); 
  

  我期望的函数返回350从每周柱回升。但如果wepn是30，而不是60，我期望210回来（从7 * wepn价格计算）。

  在SP代码IM测试：

  DELIMITER $$ 
  
  
  CREATE procedure tmp_get_price(myid INT) 
  
  BEGIN 
  
      DECLARE done INT DEFAULT 0; 
  
  
      DECLARE price decimal(30,3) default 100000.000; 
  
  
      DECLARE id INT; 
      DECLARE prop_id INT; 
      DECLARE type enum('catered','selfcatered'); 
      DECLARE name varchar(45); 
  
      DECLARE `from` date; 
      DECLARE `to` date; 
  
      DECLARE currency varchar(45); 
      DECLARE so tinyint; 
      DECLARE wk decimal(30,3); 
      DECLARE wepn decimal(30,3); 
  
      DECLARE wdpd decimal(30,3); 
      DECLARE monthly decimal(30,3); 
      DECLARE extra decimal(30,3); 
      DECLARE pppn decimal(30,3); 
      DECLARE pn decimal(30,3); 
  
      DECLARE pppw decimal(30,3); 
      DECLARE minstay int; 
      DECLARE maxstay int; 
      DECLARE breakfast varchar(45); 
      DECLARE annual TINYINT; 
  
  
  
      DECLARE cur1 CURSOR FOR SELECT id, prop_id, type, name, `from`, `to`, currency, so, wk, wepn, wdpd, minstay, maxstay, monthly, extra, pppn, pn, pppw, breakfast, annual FROM rental_periods WHERE prop_id = myid; 
      DECLARE CONTINUE HANDLER FOR NOT FOUND SET done = 1; 
  
      OPEN cur1; 
  
  
      REPEAT 
      FETCH cur1 INTO id, prop_id, type, name, `from`, `to`, currency, so, wk, wepn, wdpd, minstay, maxstay, monthly, extra, pppn, pn, pppw, breakfast, annual; 
  
  
      IF NOT done THEN 
      IF (type = "selfcatered") THEN 
  
       IF (wdpd > 0 AND (wdpd * 7) < price) THEN 
        SET price = wdpd * 7; 
       END IF; 
  
  
       IF (wepn > 0 AND (wepn * 7) < price) THEN 
        SET price = wepn * 7; 
       END IF; 
  
  
       IF ((wdpd > 0 AND wepn > 0) AND 
        (wdpd * 5 + wepn * 2) < price) THEN 
        SET price = wdpd * 5 + wepn * 2; 
       END IF; 
  
  
       IF (monthly > 0 AND (monthly/(52/12)) < price) THEN 
        SET price = monthly/(52/12); 
       END IF; 
  
  
       IF (wk > 0 AND wk < price) THEN 
        SET price = wk; 
       END IF; 
      ELSE 
       IF (pppn > 0 AND (pppn * 7) < price) THEN 
        SET price = pppn * 7; 
       END IF; 
  
       IF (pn > 0 AND (pn * 7) < price) THEN 
        SET price = pn * 7; 
       END IF; 
  
       IF (pppw > 0 AND (pppw) < price) THEN 
        SET price = pppw; 
       END IF; 
      END IF; 
  
  
      END IF; 
      UNTIL done END REPEAT; 
  
      CLOSE cur1; 
  
      select price; 
  END $$ 
  

  仍然不工作... :(我是不是傻了无法看到为什么这不会工作.. 得到时期..？！？ 。 去throught每一个... 如果价格更低设置.... 选择价格....？！？

  ，如果我把多选择在...例如光标内。 只有最下面的一个火灾和返回100000.000

  我设置的所有值字段，小数和不允许空...

  任何想法，当我去错了...？也尝试通过插入到日志表中进行调试...从来没有触发..？！

Answer 1

需要阅读更多有关游标这个接缝一个很好的开始...

http://www.kbedell.com/2009/03/02/a-simple-example-of-a-mysql-stored-procedure-that-uses-a-cursor/