我有一个关键字:列表对的字典。列表是字符串列表,但它们需要是整数。下面是什么我开始用一个例子:转换键:字符串列表键:字典中整数列表
dictionary = {
"P4021a": ["1","2","3","4","5"],
"P4019a": ["1","2","3","4","5"],
"P4013a": ["1","2","3","4","5"]
}
我试图实现以下目标:
dictionary = {
"P4021a": [1,2,3,4,5],
"P4019a": [1,2,3,4,5],
"P4013a": [1,2,3,4,5]
}
这里是我到目前为止已经试过:
new_dict = {}
for key in dictionary.keys():
new_dict[key] = dictionary[int(key)]
我收到一个错误,指出int()无法在列表上操作。所以我也试着在每个列表中添加迭代。
new_dict = {}
for key in dictionary.keys():
new_dict[key] = dictionary[[int(value) for value in dictionary.values() for i in range(5)]]
我也试过:
new_dict = {}
for key in dictionary.keys():
new_dict[key] = dictionary[map(int,key)]
任何帮助表示赞赏。
做一些关于代码的解释。代码转储通常是不被接受的。 –