由于某种原因,当我尝试执行此PHP代码时,我的第一个选择命令失败,我找不到原因。任何帮助,将不胜感激。会话开始很好,据我所知,当我从产品表执行查询选择时问题出现了。它已被正确定义,并且所有值都已正确插入,否则其他站点Products将无法正确显示。但我无法添加任何东西到我的购物车显然是由于我的选择命令的问题。SELECT命令失败会有原因吗?
<?php
session_start();
$productID = $_POST["productID"];
$cartNumber = $_SESSION["cartNumber"];
require_once('appVars.php');
$dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME)
or die('Could not connect to MySQL server as CIS55Student, cis55 database.');
$query = "SELECT * FROM products_nalanirowe WHERE productID = '$productID'";
$rs = mysqli_connect($dbc, $query) or die('SELECT command failed. ' . mysqli_error($dbc));
$num_rows = mysqli_num_rows($rs);
$row = mysqli_fetch_array($rs);
$productName = $row['productName'];
$productPrice = $row['productPrice'];
if ($cartNumber <> "") {
$query = "SELECT * FROM cart_nalanirowe WHERE cartNumber = '$cartNumber' and ProductID = '$productID'";
$rs = mysqli_connect($dbc, $query) or die('SELECT command failed. ' . mysqli_error($dbc));
$num_rows = mysqli_num_rows($rs);
if ($num_rows == 0) {
$query = "INSERT INTO cart_nalanirowe VALUES ('$cartNumber', '$productID', '$productName', CURDATE(), CURTIME())";
$rs = mysqli_connect($dbc, $query) or die('INSERT INTO command failed. ' . mysqli_error($dbc));
}
else {
}
}
else {
$query = "SELECT * FROM cart_nalanirowe ORDER BY cartNumber DESC";
$rs = mysqli_connect($dbc, $query) or die('SELECT command failed. ' . mysqli_error($dbc));
echo '<br>Selected record from table cart_nalanirowe';
$row = mysqli_fetch_array($rs);
$lastCartNumber = $row['cartNumber'];
$newCartNumber = $lastCartNumber + 1;
$query = "INSERT INTO cart_nalanirowe VALUES ('$newCartNumber', '$productID', '$productPrice', CURDATE(), CURTIME())";
$rs = mysqli_connect($dbc, $query) or die('INSERT INTO command failed. ' . mysqli_error($dbc));
$_SESSION["cartNumber"] = $newCartNumber;
}
mysqli_close($dbc);
ob_start();
header("Location: viewcart.php");
ob_flush();
?>
我敢打赌,如果您将您的代码缩小到有问题的部分,您的问题将更加重视。很多人会看你的代码,认为“没有办法”,接下来的问题。 – Amarnasan
要执行查询,请使用'mysqli_query($ dbc,$ query)',而不是'mysqli_connect()'。 –
你为什么要用“mysqli_connect”查询 –