从Python嵌套字典中打印int值，'int'对象不可迭代

我试图访问嵌套的JSON文件，并通过将它们导入python字典来打印它的数据。当我将它们打印出来时，最后一个值是来自字典的int值。从Python嵌套字典中打印int值，'int'对象不可迭代

这是我的JSON数据

{ 
"time": { 
    "Thursday": { 
     "21:00": 4, 
     "1:00": 1, 
     "4:00": 1, 
     "2:00": 1, 
     "20:00": 2, 
     "22:00": 1, 
     "19:00": 1, 
     "15:00": 2, 
     "13:00": 1, 
     "23:00": 2 
    }, 
    "Wednesday": { 
     "11:00": 2, 
     "13:00": 2, 
     "14:00": 1, 
     "17:00": 1, 
     "6:00": 1, 
     "2:00": 1, 
     "0:00": 2, 
     "1:00": 1, 
     "21:00": 1, 
     "18:00": 1, 
     "19:00": 1, 
     "20:00": 2 
    }, 
    "Sunday": { 
     "18:00": 1, 
     "16:00": 1, 
     "14:00": 1, 
     "19:00": 2, 
     "17:00": 1, 
     "23:00": 1, 
     "21:00": 1, 
     "20:00": 5, 
     "6:00": 1, 
     "0:00": 1, 
     "2:00": 2, 
     "3:00": 3 
    }, 
    "Friday": { 
     "16:00": 1, 
     "14:00": 2, 
     "10:00": 2, 
     "23:00": 1, 
     "19:00": 2, 
     "18:00": 1, 
     "15:00": 1, 
     "21:00": 2, 
     "22:00": 2, 
     "3:00": 1, 
     "0:00": 2 
    }, 
    "Saturday": { 
     "21:00": 1, 
     "23:00": 3, 
     "18:00": 4, 
     "10:00": 1, 
     "12:00": 1, 
     "13:00": 3, 
     "14:00": 1, 
     "15:00": 1, 
     "16:00": 2, 
     "17:00": 3, 
     "2:00": 1, 
     "0:00": 1, 
     "1:00": 2 
    }, 
    "Monday": { 
     "12:00": 1, 
     "11:00": 1, 
     "14:00": 1, 
     "18:00": 1, 
     "19:00": 1, 
     "23:00": 1, 
     "20:00": 1 
    }, 
    "Tuesday": { 
     "18:00": 2, 
     "12:00": 1, 
     "13:00": 2, 
     "16:00": 1, 
     "15:00": 1, 
     "4:00": 1, 
     "21:00": 1, 
     "20:00": 2, 
     "23:00": 2 
    } 
}, 
"business_id": "7KPBkxAOEtb3QeIL9PEErg"

}

这是我的Python代码：

import json 
with open('dataset/sample-checkin.json') as json_data: 
    d = json.load(json_data) 

for day in d["time"]: 
    for time in d["time"][day]: 
     for checkin in d["time"][day][time]: 
      print(day, time, checkin)

错误：在d签到[ “时间”] [天] [时间]：TypeError：'int'对象不可迭代

来源

2017-10-08 Huy Le

最后一个循环没有意义......没有任何东西在那里循环。（值为，如错误所示，int。）我想你可能想要这样的东西：

for day in d["time"]: 
    for time in d["time"][day]: 
     checkin = d["time"][day][time] 
     print(day, time, checkin)

来源

2017-10-08 04:39:38 smarx

从Python嵌套字典中打印int值，'int'对象不可迭代

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