根据特定日期范围在一个月内汇总多个列

Question

我需要汇总Amounts以按月份的日期范围显示。为了说明请大家看看下面的表中：

Invoice_Payment

Customer_id Invoice_no Invoice_date Amount 
--------------------------------------------------- 
10    10023   2016-07-08  60 
10    10018   2016-08-04  90 
11    10016   2016-07-01  110 
11    10021   2016-07-05  120 
12    10028   2016-07-11  10 
12    10038   2016-07-31  5 

正如您看到的，我想他们基于Customer_id组和从头到尾显示的日期。此外，这只能在每个月进行。

下面的查询到目前为止，我曾尝试：

select Customer_id, (mindate + ' to ' + maxdate) Date_Range, Amount 
from (
    select Customer_id, sum(Amount) Amount, min(Invoice_date) mindate, max(Invoice_date) maxdate 
    from Invoice_Payment 
    group by Customer_id 
    ) I ; 

从上面查询我越来越喜欢Output：

Customer_id Date_Range     Amount 
10    2016-07-08 to 2016-08-04  150 
11    2016-07-01 to 2016-07-05  230 
12    2016-07-11 to 2016-07-31  15 

请检查这个.. SQL Fiddle Working Demo

比方说， Customer_id = 10谁在July,2016和中有Invoice_date。我需要在特定日期范围内分别总结该特定客户在七月份和八月份的所有付款。但是我从上面的努力获得所有Invoice_date的Amount的总和。

所需的输出：

Customer_id Date_Range     Amount 
10    2016-07-08 to 2016-07-08  60 
10    2016-08-04 to 2016-08-04  90 
11    2016-07-01 to 2016-07-05  230 
12    2016-07-11 to 2016-07-31  15 

我怎么能渡过这个？任何帮助将不胜感激。

Answer 1

快要大功告成。只需添加YEAR和MONTH至GROUP BY即可。

select Customer_id, (mindate + ' to ' + maxdate) Date_Range, Amount 
from (
     select Customer_id, 
     sum(Amount) Amount, min(Invoice_date) mindate, max(Invoice_date) maxdate 
     from #Invoice_Payment 
group by 
    Customer_id, 
    YEAR(Invoice_date), 
    MONTH(Invoice_date) 
) I ; 

Answer 2

如何逐年CUSTOMER_ID，一个月分组和

select Customer_id, (mindate + ' to ' + maxdate) Date_Range, Amount 
from (
     select Customer_id, 
     sum(Amount) Amount, min(Invoice_date) mindate, max(Invoice_date) maxdate 
     from #Invoice_Payment 
     group by Customer_id,month(Invoice_date), year(Invoice_date) 
) I 
order by customer_id;