我有2个日期范围数组我试图找出区别。 让我们用数字,例如:如何区分日期范围的2个数组之间的区别?
我有2米范围[1-7, 9-16]
,我想减去[2-3, 7-9, 14-20]
并获得[1-1, 4-6, 10-13]
结果的范围,我陷入一个有点车辙试图弄清楚的。当然有一个我不知道的通用解决方案?
diffDateRangesArray(rangesArray1, rangesArray2) {
//rangesArray = [{startDate, endDate}]
let diffedRanges = [];
rangesArray1.forEach(function(range1){
//loop through rangesArray2 removing from range1
rangesArray2.forEach(function(range2){
// breaks if array returned
// perhaps should always return array and flatten?
range1 = diffDateRanges(range1, range2);
});
diffedRanges.push(range1);
});
//probably should do some sort of union here
return diffedRanges;
}
diffDateRanges(range1, range2) {
//range = {startDate, endDate}
let diffedRange = {};
// if not in range
if(range2.endDate <= range1.startDate || range2.startDate >= range1.endDate){
return range1;
//if envelops range
} else if(range2.endDate >= range1.endDate && range2.startDate <= range1.startDate){
return null;
//if cuts off end of range
} else if(range2.startDate <= range1.endDate && range2.endDate >= range1.endDate){
return {startDate:range1.startDate, endDate: range2.startDate};
// if cuts off start of range
} else if(range2.endDate >= range1.startDate && range2.startDate <= range1.startDate){
return {startDate:range2.endDate, endDate: range1.endDate};
// if inside of range - should better handle arrays
} else if(range2.startDate >= range1.startDate && range2.endDate <= range1.endDate){
return [
{startDate:range1.startDate, endDate: range2.startDate},
{startDate:range2.endDate, endDate: range1.endDate},
];
}
}
我没有得到如何减去'[2-3,7-9,14-20]''从[1-7 ,9-16]'会导致'[1-1,4-6,10-13]'......你能否更详细地解释这一部分,什么是从什么等中减去的? –
怎么样:我有数字'[1,2,3,4,5,6,7,9,10,11,12,13,14,15,16]',我想删除'[2 ,3,7,8,9,14,15,16,17,18,19,20]',导致'[1,4,5,6,10,11,12,13]' - 但是输入并且输出需要是带有“{start,end}”的对象而不是一系列。这可能给了我一个想法... –
我想我只需要将'{start,end}'对象转换成一个数组,并区分它们!然后将它翻译回一个'{start,end}'阵列 –