查找包含字符串集特定字词蟒蛇

后如何搜索词“视图”和字“U”一样，如果它是u'myprofile.view_department'然后从该长的字符串/款获得myprofile, view, department - 新的Python -查找包含字符串集特定字词蟒蛇

set([u'auth.view_group', u'auth.add_user', u'transaction.change_sender', u'myprofile.view_department', u'auth.add_permission', u'transaction.add_receiver', u'myprofile.delete_routineusers', u'transaction.change_receiver', u'sessions.change_session', u'transaction.delete_receiver', u'registration.change_registrationprofile', u'auth.view_user', u'auth.delete_permission', u'transaction.view_sender', u'myprofile.change_hrworker', u'registration.add_registrationprofile', u'admin.view_logentry', u'registration.view_registrationprofile', u'contenttypes.change_contenttype', u'myprofile.view_routineusers', u'sessions.delete_session', u'myprofile.change_department', u'myprofile.delete_hrworker', u'admin.change_logentry', u'myprofile.change_allusers', u'admin.delete_logentry', u'transaction.delete_sender', u'auth.add_group', u'myprofile.delete_department', u'myprofile.add_department', u'contenttypes.delete_contenttype', u'auth.view_permission', u'myprofile.add_allusers', u'myprofile.delete_allusers', u'auth.change_permission', u'transaction.view_receiver', u'auth.change_group', u'registration.delete_registrationprofile', u'contenttypes.view_contenttype', u'sessions.add_session', u'auth.delete_group', u'auth.delete_user', u'myprofile.view_hrworker', u'transaction.add_sender', u'myprofile.add_hrworker', u'admin.add_logentry', u'sessions.view_session', u'auth.change_user', u'myprofile.add_routineusers', u'contenttypes.add_contenttype', u'myprofile.view_allusers', u'myprofile.change_routineusers'])

我的尝试：

l = request.user.get_all_permissions().split() 
       if any(word in all_text for word in l): 
        print 'found one of em' 


l = request.user.get_all_permissions().split() 
      l11 = [elem.strip().split(',') for elem in l] 
      l11 = [] 
      for elem in l: 
       l11.extend(elem.strip().split(',')) 
      print l1

这样的代码生成属性错误'set' object has no attribute 'split'我知道这点到set([但如何从这个获得几句话？如果你使用split()

>>> str = "set([u'auth.view_group', u'auth.add_user', u'transaction.change_sender', u'myprofile.view_department', u'auth.add_permission', u'transaction.add_receiver', u'myprofile.delete_routineusers', u'transaction.change_receiver', u'sessions.change_session', u'transaction.delete_receiver', u'registration.change_registrationprofile', u'auth.view_user', u'auth.delete_permission', u'transaction.view_sender', u'myprofile.change_hrworker', u'registration.add_registrationprofile', u'admin.view_logentry', u'registration.view_registrationprofile', u'contenttypes.change_contenttype', u'myprofile.view_routineusers', u'sessions.delete_session', u'myprofile.change_department', u'myprofile.delete_hrworker', u'admin.change_logentry', u'myprofile.change_allusers', u'admin.delete_logentry', u'transaction.delete_sender', u'auth.add_group', u'myprofile.delete_department', u'myprofile.add_department', u'contenttypes.delete_contenttype', u'auth.view_permission', u'myprofile.add_allusers', u'myprofile.delete_allusers', u'auth.change_permission', u'transaction.view_receiver', u'auth.change_group', u'registration.delete_registrationprofile', u'contenttypes.view_contenttype', u'sessions.add_session', u'auth.delete_group', u'auth.delete_user', u'myprofile.view_hrworker', u'transaction.add_sender', u'myprofile.add_hrworker', u'admin.add_logentry', u'sessions.view_session', u'auth.change_user', u'myprofile.add_routineusers', u'contenttypes.add_contenttype', u'myprofile.view_allusers', u'myprofile.change_routineusers'])" 
>>> import re 
>>> pat = re.compile('(?<=u\')([a-z]+).([a-z]+).([a-z]+)') 
>>> pat.findall(str) 
[('auth', 'view', 'group'), ('auth', 'add', 'user'), ('transaction', 'change', 'sender'), ('myprofile', 'view', 'department'), ('auth', 'add', 'permission'), ('transaction', 'add', 'receiver'), ('myprofile', 'delete', 'routineusers'), ('transaction', 'change', 'receiver'), ('sessions', 'change', 'session'), ('transaction', 'delete', 'receiver'), ('registration', 'change', 'registrationprofile'), ('auth', 'view', 'user'), ('auth', 'delete', 'permission'), ('transaction', 'view', 'sender'), ('myprofile', 'change', 'hrworker'), ('registration', 'add', 'registrationprofile'), ('admin', 'view', 'logentry'), ('registration', 'view', 'registrationprofile'), ('contenttypes', 'change', 'contenttype'), ('myprofile', 'view', 'routineusers'), ('sessions', 'delete', 'session'), ('myprofile', 'change', 'department'), ('myprofile', 'delete', 'hrworker'), ('admin', 'change', 'logentry'), ('myprofile', 'change', 'allusers'), ('admin', 'delete', 'logentry'), ('transaction', 'delete', 'sender'), ('auth', 'add', 'group'), ('myprofile', 'delete', 'department'), ('myprofile', 'add', 'department'), ('contenttypes', 'delete', 'contenttype'), ('auth', 'view', 'permission'), ('myprofile', 'add', 'allusers'), ('myprofile', 'delete', 'allusers'), ('auth', 'change', 'permission'), ('transaction', 'view', 'receiver'), ('auth', 'change', 'group'), ('registration', 'delete', 'registrationprofile'), ('contenttypes', 'view', 'contenttype'), ('sessions', 'add', 'session'), ('auth', 'delete', 'group'), ('auth', 'delete', 'user'), ('myprofile', 'view', 'hrworker'), ('transaction', 'add', 'sender'), ('myprofile', 'add', 'hrworker'), ('admin', 'add', 'logentry'), ('sessions', 'view', 'session'), ('auth', 'change', 'user'), ('myprofile', 'add', 'routineusers'), ('contenttypes', 'add', 'contenttype'), ('myprofile', 'view', 'allusers'), ('myprofile', 'change', 'routineusers')]

来源

2014-04-30 Tameen Malik

是你可以但如果我尝试了100次 –

请出示你已经尝试了什么。 –

你不需要这样的正则表达式，检查字符串中的''.view_'，然后使用'str.partition'。 –

试试这个

s = u'myprofile.view_department' 
temp = s.split('.') 
words = [temp[0]] + temp[1].split('_') 
print words 
# [u'myprofile', u'view', u'department']

来源

2014-04-30 06:46:32 aelor

我认为OP有一组字符串而不是set对象的字符串表示。 –

@Aशwiniचhaudhar ohh对不起伙伴，问题在初始格式化 – aelor

@elor错误已生成：'期望的字符串或缓冲区' –

简单：

来源

2014-04-30 06:50:13 0605002

请查看我更新的问题 –

查找包含字符串集特定字词蟒蛇

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