自定义手势不发送动作消息

Question

我创建了一个UIGestureRecognizer子类，称为LongPressGestureRecognizer模拟长按手势。 （是的，我知道已经存在，我只是学习Objective-C和试验了一下具体子类）。

我也只覆盖了以下方法：

- (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event 
{ 
    self.state = UIGestureRecognizerStatePossible; 
    [self performSelector:@selector(setState:) withObject:[NSNumber numberWithInt:UIGestureRecognizerStateRecognized] afterDelay:2]; 
} 

- (void)touchesCancelled:(NSSet *)touches withEvent:(UIEvent *)event 
{ 
    [NSObject cancelPreviousPerformRequestsWithTarget:self]; 
    self.state = UIGestureRecognizerStateCancelled; 
} 

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event 
{ 
    [NSObject cancelPreviousPerformRequestsWithTarget:self]; 
    self.state = UIGestureRecognizerStateFailed; 
} 

在我看来，控制器属性recognizer存储手势识别器，我有以下代码：

- (LongPressGestureRecognizer *)recognizer 
{ 
    if (!_recognizer) { 
     _recognizer = [[LongPressGestureRecognizer alloc] init]; 
    } 
    return _recognizer; 
} 

- (void)viewDidLoad 
{ 
    [super viewDidLoad]; 
    [self.recognizer addTarget:self action:@selector(log:)]; 

    [self.view addGestureRecognizer:self.recognizer]; 
} 

- (IBAction)log:(LongPressGestureRecognizer *)recognizer 
{ 
    //blah blah blah 
} 

我的问题是log:是没有得到所谓的在所有...通过在控制台登录的UIGestureRecogniserState S，我知道手势识别器正在工作，只要状态而言预计...

我在做什么错在这里？

Answer 1

也可能有其他问题，但我可以告诉你，你的电话不会像你希望的那样工作;你会最终传递的指针NSNumber对象，而不是一个int的，所以state将被设置为某种垃圾的价值。创建一个方法，将执行self.state = UIGestureRecognizerStateRecognized并调用它。