Laravel查询字符串少/大于等

Question

在laravel，我可以在一个资源控制器写这篇文章，以获得响应的请求（假设资源是产品）：

public function index(Request $request) 
{ 
    // Handles requests such as ".../api/products?user_id=5&price=500" 
    $products = Product::where($request->toArray())->get(); 
    return response($products); 
} 

也能正常工作与要求“=”，例如在这个例子中。但是如果我们不想搜索价格= 500，但可能价格< = 500或价格> 500，那该怎么办？最好的Laravel（和RESTful）方法是什么？

注意：Laravel 5.2

Answer 1

你可以这样做。

public function index(Request $request) 
{ 
    // Handles requests such as ".../api/products?user_id=5&price=500" 
    $products = Product::where('user_id', $request->user_id)->where('price', '<=', intval($request->price))->get(); 
    return response()->json($products); 
} 

或者：@Joel欣茨评论后

public function index(Request $request) 
{ 
    // Handles requests such as ".../api/products?user_id=5&price=500" 
    $products = Product::whereRaw("user_id=? and price<=?", [$request->user_id, $request->price])->get(); 
    return response()->json($products); 
} 

编辑：

如果您还想传递查询的操作符，你可以添加一个新的参数到网址，例如

/api/products?user_id=5&price=500&op=1 

然后切换控制器中的号码。

public function index(Request $request) 
{ 
    // Handles requests such as ".../api/products?user_id=5&price=500&op=1" 
    switch(intval($request->op)){ 
     case 1: 
     $op = "<="; 
     break; 

     case 2: 
     $op = ">"; 
     break; 

     //and so on 

     default: 
     return response()->json("Wrong parameters"); 
     break; 
    } 

    $products = Product::whereRaw("user_id = ? and price $op ?", [$request->user_id, $request->price])->get(); 
    return response()->json($products); 
}