反序列化JSON值到列表

Question

嗯，我经历过多次的问题，现在同样的事情，还是斜面了解Newtonsoft是如何工作的完全。

从网页的响应是，

{"status":[{"domain":"test.com","zone":"com","status":"active","summary":"active"}]} 

我已在类解析制成，

public class Status 
{ 
    public string name { get; set; } 
    public string zone { get; set; } 
    public string status { get; set; } 
    public string summary { get; set; } 
} 

而且DeserializeObject

IList<Status> domains = new List<Status>(); 
domains = JsonConvert.DeserializeObject<List<Status>>(src); 

，但它仍然不要执行的DeserializeObject，它使返回错误，

An exception of type 'Newtonsoft.Json.JsonSerializationException' occurred in Newtonsoft.Json.dll but was not handled in user code 
Additional information: Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type 'System.Collections.Generic.List`1[Domain_Checker.Status]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly. 
To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List<T>) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object. 

任何想法吗？

Answer 1

根据您的JSON，你需要一个根对象

public class Root 
{ 
    public List<Status> Status {get;set;} 
} 

---

var root = JsonConvert.DeserializeObject<Root>(src); 

Answer 2

已经有回答如何将这个JSON解析到自己的对象。如果你不需要，你可以将json转换为JObject。从JObject你可以检索你想要这样的任意值：

var json = {"status":[{"domain":"test.com","zone":"com","status":"active","summary":"active"}]}; 

var jsonObject = JObject.Parse(json); 
var jsonProperty = jsonObject["status"][0]["domain"]; 

Answer 3

对于在[JsonProperty("domain")] public string name { get; set; } deseralizing您需要的类结构像这样

public class Status 
{ 
    [JsonProperty("domain")] 
    public string name { get; set; } 
    [JsonProperty("zone")] 
    public string zone { get; set; } 
    [JsonProperty("status")] 
    public string status { get; set; } 
    [JsonProperty("summary")] 
    public string summary { get; set; } 
} 

public class ClsStatus 
{ 
    [JsonProperty("status")] 
    public List<Status> status { get; set; } 
} 

的JSON现在，如果你仔细看看我已经使用了名称而不是域名。但仍deseralization会因为JsonProperty来完成。

只是反序列化舒服就好。

string jsonstr = File.ReadAllText("YourJSONFile"); 
ClsStatus csObj = JsonConvert.DeserializeObject<ClsStatus>(JsonStr);