1
获得对象的名单我想使用akka-http-spray-json 10.0.9
spray-json。如何从JSON
我的模型:
case class Person(id: Long, name: String, age: Int)
我得到JSON字符串jsonStr
与人的名单,并尝试分析它:
implicit val personFormat: RootJsonFormat[Person] = jsonFormat3(Person)
val json = jsonStr.parseJson
val persons = json.convertTo[Seq[Person]]
错误:
Object expected in field 'id'
可能是我需要创建implicit object extends RootJsonFormat[List[Person]]
并覆盖read
和write
方法。
implicit object personsListFormat extends RootJsonFormat[List[Person]] {
override def write(persons: List[Person]) = ???
override def read(json: JsValue) = {
// Maybe something like
// json.map(_.convertTo[Person])
// But there is no map or similar method :(
}
}
P.S.对不起,我的英语不是我的母语。
UPD
jsonStr:
[ {"id":6,"name":"Martin Ordersky","age":50}, {"id":8,"name":"Linus Torwalds","age":43}, {"id":9,"name":"James Gosling","age":45}, {"id":10,"name":"Bjarne Stroustrup","age":59} ]
我得到了'找不到类型CustomCollectionFormats' – Oleg
对不起..这来自于我们自己的lib .. –
对不起,编辑和不相关的评论..我的scala repl命名空间充满了左转.. –