使更高或更低的游戏运行Python 3的问题。多个if语句

Question

我有多个if语句的问题。我明白我的代码有什么问题，但我找不到解决方案。所以当我运行该程序时，“较高”部分可以工作，但如果我猜“较低”部分则不能。解释者从阅读if语句到elif语句。那不是我想要的。如何在使用elif语句前先检查两个语句。我试过嵌套如果但我似乎无法得到它的工作。 在此先感谢。

# Higher or lower card game 

import random 

x = random.randint(1, 14) 

y = random.randint(1, 14) 

print('The number is ', x, '.') 

while True: 

    print('higher or lower?') 
    if input() in {'higher', 'h'} and y >= x: 
     print('Good guess the number was ', y) 
     x = y 
     y = random.randint(1, 14) 
    elif y < x: 
     print('Bad guess , the number was ', y) 
     break 
    if input() in {'lower', 'l'} and y < x: 
     print('Good guess, the number was ', y) 
     x = y 
     y = random.randint(1, 14) 
    elif y >= x: 
     print('Bad guess, the number was ', y) 
     break 
    continue 

Answer 1

你可能想沿着线的东西：

while True: 

    print('higher or lower?') 
    ans_in = input() 

    if ans_in in {'higher', 'h'}: 

     if (y >= x): 
      print('Good guess the number was ', y) 
      x = y 
      y = random.randint(1, 14) 

     elif (y < x): 
      print('Bad guess , the number was ', y) 
      break 

    elif ans_in in {'lower', 'l'}: 

     if (y < x): 
      print('Good guess, the number was ', y) 
      x = y 
      y = random.randint(1, 14) 

     elif (y >= x): 
      print('Bad guess, the number was ', y) 
      break 

    continue 

请注意，由于break语句的，一个“坏猜”将结束游戏。如果你想继续获得“糟糕的猜测”，你可以简单地删除break语句。

Answer 2

我猜测是不行的，因为你在每个周期中得到两次输入。

你应该试试这个：

import random 

x = random.randint(1, 14) 

y = random.randint(1, 14) 

print('The number is ', x, '.') 

while True: 

    print('higher or lower?') 
    guess = input() 
    if guess in {'higher', 'h'} and y >= x: 
     print('Good guess the number was ', y) 
     x = y 
     y = random.randint(1, 14) 
    elif guess in {'higher', 'h'} and y < x: 
     print('Bad guess , the number was ', y) 
     break 
    elif guess in {'lower', 'l'} and y < x: 
     print('Good guess, the number was ', y) 
     x = y 
     y = random.randint(1, 14) 
    elif guess in {'lower', 'l'} and y >= x: 
     print('Bad guess, the number was ', y) 
     break 
    else: 
     print('Invalid command') 
     break 
    continue 

所以基本上每次迭代中你只需要输入一个命令，并根据你建立你的逻辑。