我使用AJAX(jQuery)将表单提交给PHP脚本。
这里是JavaScript:
// Validate form fields
$(function() {
//Check to see if email is not empty
if (email == "") {
$("label#email_error").show();
$("input#email").focus();
return false;
}
var dataString = 'firstname=' + firstname + '&email=' + email + '&lastname=' + lastname;
$.ajax({
type: "POST",
url: "/",
data: dataString,
success: function() {
var counter = <?php echo($counter['count'] + 1); ?>
counter = numberWithCommas(counter);
$('#counter').html(counter);
$('#contact_form').html("<div id='message'></div>").fadeIn(1500, function() {
$('#message').html("<h2>Thanks " + (firstname) + "!</h2>").append("<p>We will be in touch soon.</p>");
});
}
});
return false;
});
在PHP脚本我有这样的代码:
if (!empty($_POST)){
$adestra = $this->adestraAction('contact.create' , array('1', array('1.email' => $_POST['email'] , '1.forename' => $_POST['firstname'] , '1.surname' => $_POST['lastname'],'1.source' => 'signupbox')));
$add = $this->addToListAction($adestra, $magazineID);
}
的$ _ POST可变因素似乎并没有被得到设定。任何人都可以帮忙吗?
你可以发布ajax查询吗?或者在你的php文件中,如果你打印post变量,你会得到什么? <?php print_r($ _ POST);?> – 2012-08-06 14:21:27
你可以发布jQuery代码吗?也许它正在做一个GET请求,但即使没有,看到代码将有所帮助 – 2012-08-06 14:22:38
当然,ajax查询是: – richelliot 2012-08-06 14:23:12