无法在AJAX中获取正确的状态代码错误处理程序

Question

我无法在AJAX请求的错误处理程序中获取正确的错误代码。每次发生错误，则返回我的StatusCode = 500。我想在我的服务明确地将它设置为HttpContext.Current.Response.StatusCode = 403;，但它仍然给了我状态= 500

这是我的AJAX请求看起来像：

$.ajax({ 
      type: "POST", 
      url: "Services/someSvc.asmx/SomeMethod", 
      cache: true, 
      contentType: "application/json; charset=utf-8", 
      data:"{}", 
      dataType: "json" 
      error: ajaxFailed 
     }); 

     function ajaxFailed(xmlRequest) { 
       alert(xmlRequest.status + ' \n\r ' + //This is always 500. 
       xmlRequest.statusText + '\n\r' + 
       xmlRequest.responseText); 
     } 

我在这里失踪了什么？

Answer 1

看起来你是几乎没有，这里有一个例子[的WebMethod]，将抛出的StatusCode 403

[WebMethod] 
    public static string HelloWorld(string name) 
    { 
     HttpContext.Current.Response.Clear(); 
     HttpContext.Current.Response.StatusCode = 403; 
     return null; 
    } 

这里是调用jQuery代码。

$(document).ready(function() 
    { 
     var jsonRequest = { name: "Zach Hunter" }; 

     $.ajax({ 
      type: 'POST', 
      url: 'Demo.aspx/HelloWorld', 
      data: JSON.stringify(jsonRequest), 
      contentType: 'application/json; charset=utf-8', 
      dataType: 'json', 
      success: function (data, text) 
      { 
       $('#results').html(data.d); 
      }, 
      error: function (request, status, error) 
      { 
       $('#results').html('Status Code: ' + request.status); 
      } 
     }); 
    }); 

如果您没有返回方法签名中指定的值，则会返回状态码500。

Answer 2

根据the documentation：

error(jqXHR, textStatus, errorThrown)

A function to be called if the request fails. The function receives three arguments: The jqXHR (in jQuery 1.4.x, XMLHttpRequest) object, a string describing the type of error that occurred and an optional exception object, if one occurred. Possible values for the second argument (besides null) are "timeout", "error", "abort", and "parsererror". When an HTTP error occurs, errorThrown receives the textual portion of the HTTP status, such as "Not Found" or "Internal Server Error." As of jQuery 1.5, the error setting can accept an array of functions. Each function will be called in turn. Note: This handler is not called for cross-domain script and JSONP requests. This is an Ajax Event.

所以你的代码更改为更具这样的：

$.ajax({ 
    type: "POST", 
    url: "Services/someSvc.asmx/SomeMethod", 
    cache: true, 
    contentType: "application/json; charset=utf-8", 
    data:"{}", 
    dataType: "json", 
    error: ajaxFailed (jqXHR, textStatus, errorThrown) 
}); 

function ajaxFailed(jqXHR, textStatus, errorThrown) { 
    alert(errorThrown + ' \n\r ' + textStatusText);   
} 

您也可能会发现this answer provides some additional信息。