0
我有DetailsView嵌套在GridView中,我无法弄清楚如何传递值(如GridView中的项目ID和会话中的值)到插入方法的参数。嵌套DetailsView插入方法的参数
<asp:DetailsView ID="DetailsViewPostLikes" runat="server"
AutoGenerateRows="false" DataSourceID="odsPostLikes"
DataKeyNames="id" GridLines="None">
<Fields>
<asp:CommandField ShowInsertButton="true" InsertText="Like" newtext="Like" />
<asp:TemplateField HeaderText="" SortExpression="Nickname">
<ItemTemplate>
<asp:Label id="nicknamelikesCount" runat="server" Text='<%# Bind("LikeCount") %>'></asp:Label> people likes this.
</ItemTemplate>
</asp:TemplateField>
</Fields>
</asp:DetailsView>
<asp:ObjectDataSource ID="odsPostLikes" runat="server"
TypeName="SocWebApp.Database.PostLikeTable"
SelectMethod="Select" InsertMethod="Insert" UpdateMethod="Update">
<SelectParameters>
<asp:Parameter Name="postId" Type="Int32" />
</SelectParameters>
<InsertParameters>
<asp:Parameter Name="postId" Type="Int32" />
<asp:SessionParameter Name="userId" SessionField="User_id" Type="Int32" />
</InsertParameters>
</asp:ObjectDataSource>
我试图做同样的方式为这样的选择参数:
protected void posts_ItemDatabound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)//(GridView)e.Row.FindControl("odsComments") != null)
{
ObjectDataSource s1 = (ObjectDataSource)e.Row.FindControl("odsComments");
s1.SelectParameters["postId"].DefaultValue = DataBinder.Eval(e.Row.DataItem, "Id").ToString();
ObjectDataSource s2 = (ObjectDataSource)e.Row.FindControl("odsPostLikes");
s2.InsertParameters["postId"].DefaultValue = DataBinder.Eval(e.Row.DataItem, "Id").ToString();
ObjectDataSource s3 = (ObjectDataSource)e.Row.FindControl("odsPostLikes");
s3.InsertParameters["userId"].DefaultValue = Session["User_id"].ToString();
}
}
但只有userid参数值设置(从Session),是帖子ID始终为0
什么是合适的解决方案? 谢谢。