如何在Web客户端请求中检索custome错误消息？

Question

服务器端代码，返回文件

[HttpGet] 
public HttpResponseMessage GetVersionList(string Credentials, string VersionNumber) 
{ 
    try 
    { 
     string UserLoginStatus = objUtility.LoginUser(objUtility.GetUserName(Credentials), objUtility.GetPassWord(Credentials)); 

     if (UserLoginStatus == "OK") 
     { 
      var path = objUtility.GetFileName(VersionNumber); 

      if (path != null) 
      { 
       return FileAsAttachment(path, VersionNumber + ".exe"); 
      } 
      else 
      {    
       return Request.CreateErrorResponse(HttpStatusCode.OK, "File Not Found."); 
      } 
     } 
     else 
     { 
      // Return reason why it failed. 
      // It could be not authorized user, Not Active user, UID/Password wrong etc. 
      // Store into UserLoginStatus variable and pass show to client 
      return Request.CreateResponse<string>(HttpStatusCode.OK, UserLoginStatus); 
     } 
    } 
    catch (System.Exception ex) 
    { 
     return Request.CreateResponse<string>(HttpStatusCode.OK, ex.Message); 
    } 

} 

// Win app code to download file 
using (WebClient webClient = new WebClient()) 
{ 
      try 
      { 
       webClient.DownloadFile(serverUrl, (txtPath.Text + "\\" + txtVersion.Text + ".exe")); 
      } 
      catch (WebException wex) 
      { 
       // Show error message here 
      } 
     } 
    } 
    catch (Exception ex) 
    { 
     lblStatus.Text = ex.InnerException + " <br> " + ex.Message; 
    } 
} 

Answer 1

这是我如何做它最近休息了一会服务，我写了一个POS机。 （myErrorType就是无论什么类，你实际上是使用虚拟...）

using (var response = request.GetResponse()) 
       { 
using (var reader = new StreamReader(response.GetResponseStream())) 
          { 
           var reply = reader.ReadToEnd(); 
           myErrorType result = Newtonsoft.Json.JsonConvert.DeserializeObject<myErrorType>(reply); 
           return result.Status; 
           // do something with the results 
          } 
} 

抛出一个自定义错误：

myErrorType errresponse = new myErrorType();//dummy class, create your own... 
throw new WebFaultException<myErrorType>(errresponse, HttpStatusCode.BadRequest);