查看列联合所有列两次

Question

我想做一个联合所有产生报告的数据，下面是我到目前为止，它显示了我想要的所有数据，但我无法获取相同行中的数据，它在相应的列中最少生成两行。我希望有一种方法可以让数据在同一行中？

select account, campaign, sale, date 
from 
(
SELECT CHACCOUNTNO as account, CONTSUPREF as campaign,null as sale, ONDATE as date 
FROM   dbo.MKTDW 
WHERE  (RESULTCODE = 'D01') and CONTACT IN ('Campaign ID') 
group by CHACCOUNTNO, CONTSUPREF, ONDATE 

UNION ALL 

SELECT CHACCOUNTNO as account, null as campaign, CONTSUPREF as sale, ONDATE as date 
FROM   dbo.MKTDW 
WHERE  (RESULTCODE = 'D01') and CONTACT IN ('Order') 
group by CHACCOUNTNO, CONTSUPREF, ONDATE 
)account 
group by account,campaign,sale,date 
order by account 

当前结果：

account     campaign sale  date      
A2043056003(2IJUMI M NULL  N177618 2014-07-21 00:00:00.000 
A2043056003(2IJUMI M LT08704 NULL  2014-07-21 00:00:00.000 

预期结果：

A2043056003（2IJUMI M）LT08704 N177618 2014年7月21日00：00：00.000

Answer 1

答案将是简单的。如果你想以水平方式显示某些东西，请使用JOIN而不是SET操作符。下面列出了代码，经过测试，在SSMS中完美运行。 :)

--create table structure 
create table dbo.MKTDW 
( CHACCOUNTNO varchar(100), 
    CONTSUPREF varchar(10), 
    RESULTCODE varchar(10), 
    CONTACT varchar(50), 
    ONDATE datetime) 
go 

--insert sample data 
insert dbo.MKTDW 
select 'A2043056003(2IJUMI M)', 'N177618', 'D01', 'Order', '2014-07-21 00:00:00.000' 
union all 
select 'A2043056003(2IJUMI M)', 'LT08704', 'D01', 'Campaign ID', '2014-07-21 00:00:00.000' 
union all 
select 'B2043056003(2IJUMI M)', 'M000000', 'D01', 'Order', '2014-07-21 00:00:00.000' 
union all 
select 'B2043056003(2IJUMI M)', 'X111111', 'D01', 'Campaign ID', '2014-07-21 00:00:00.000' 


--below is the solution 
select a.CHACCOUNTNO as account, 
     a.CONTSUPREF as campaign, 
     b.CONTSUPREF as sale, 
     a.ondate as date   
from dbo.MKTDW as a 
join dbo.MKTDW as b 
on a.CHACCOUNTNO = b.CHACCOUNTNO 
where a.CONTACT = 'campaign id' 
     and b.CONTACT = 'order' 
     and a.RESULTCODE = 'D01' 
     and b.RESULTCODE = 'D01' 

结果：

Answer 2

有是不需要所有的工会和指定null ..

SELECT CHACCOUNTNO as account, CONTSUPREF as campaign,CONTSUPREF as sale, ONDATE as date 
FROM   dbo.MKTDW 
WHERE  (RESULTCODE = 'D01') and CONTACT IN ('Campaign ID','order') 
group by CHACCOUNTNO, CONTSUPREF, ONDATE 

当任何由列上述组的有NULL，NULL将被视为单独的组