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我想在我的网站上创建一个简单的登录体验。这些数据来自phpmyadmin。我遇到了麻烦,并不确定我要去哪里。我希望尽可能保持现在简单,只是为了让它开始。简单登录使用会话/ SQL
HTML
<div class="container">
<div class="row">
<div class="col-md-8 col-md-offset-2">
<div class="well well-sm">
<form class="form-horizontal" action="" method="post">
<fieldset>
<legend class="text-center">Sign In</legend>
<!-- Message body -->
<div class="form-group">
<label class="col-md-4 control-label" for="Username">Username</label>
<div class="col-md-8">
<input id="username" name="username" type="text" placeholder="Your email" class="form-control">
</div>
</div>
<div class="form-group">
<label class="col-md-4 control-label" for="Password">Password</label>
<div class="col-md-8">
<input id="password" name="password" type="text" placeholder="Your email" class="form-control">
</div>
</div>
<!-- Form actions -->
<div class="form-group">
<div class="col-md-12 text-right">
<button onClick="return validateForm()" type="submit" class="btn btn-primary btn-lg">Submit</button>
` </div>
</div>
</fieldset>
</form>
</div>
</div>
</div>
</div>
PHP
session_start();
$username=$_POST['username'];
$password=$_POST['password'];
// Connection
$conn = mysql_connect("localhost", "root", "MIS42520!$") or die (mysql_error());
//Select the database to use
mysql_select_db ("cookie", $conn);
// SQL query to fetch information of registerd users and finds user match.
$sql = mysql_query("select * from login where password='$password' AND username='$username'", $connection);
$result = mysql_query($sql, $conn) or die(mysql_error());
$row = mysql_fetch_array($sql);
if(is_array($row)) {
$_SESSION["username"] = $row[username];
$_SESSION["password"] = $row[password];
} else {
$message = "Invalid Username or Password!";
}
if(isset($_SESSION["user_id"])) {
header("Location:user_dashboard.php");
}
你得到错误? – 2014-12-07 18:01:09
'mysql_ *'函数[已弃用](http://php.net/manual/en/migration55.deprecated.php),请停止使用它们。 – 2014-12-07 18:02:21
你为什么认为数据是来自phpmyadmin?你的问题与phpMyAdmin完全无关。以及你的问题与你以前的问题有什么不同[从SQL中获取信息并将其放在表单中](http://stackoverflow.com/questions/26937084/get-information-out-of-sql-and-put-它功能于一形式)。此外,您应该首先修复基本错误,如'$ row [username]' – 2014-12-07 18:06:48