因此,我正在编写一个C++程序,在程序中运行一个命令。每当我执行命令时,它会输出一个0作为结果。例如:C++系统命令输出0在结束
The random int I was thinking of was 130
凡有只应该输出The random int I was thinking of was 13
,但它仍然在最后输出0。这里是我的代码运行命令:
printf("Running file: %s\n", fileName);
if(!exists(fileName))
{
printf("That file does not exist.\n");
return;
}
char buffer [7+strlen(fileName)];
int n;
n = sprintf(buffer, "php -f %s", fileName);
cout << system(buffer) << endl;
我不认为这有什么用php
命令,因为每当我型我到终端,php -f <filenamehere>
它与The random int I was thinking of was 13
输出出来。我想不出别的什么。
不要''cout'的system'结果的选项? –
'system()'返回0表示成功(非0表示失败)。你打印这个0. –
@MatsPetersson我怎么会输出输出? – mttprvst13